Luogu2922 [USACO08DEC]秘密消息Secret Message （Trie树）

统计以节点\(i\)结尾的数量与经过的数量

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#define R(a,b,c) for(register int  a = (b); a <= (c); ++ a)
#define nR(a,b,c) for(register int  a = (b); a >= (c); -- a)
#define Max(a,b) ((a) > (b) ? (a) : (b))
#define Min(a,b) ((a) < (b) ? (a) : (b))
#define Fill(a,b) memset(a, b, sizeof(a))
#define Abs(a) ((a) < 0 ? -(a) : (a))
#define Swap(a,b) a^=b^=a^=b
#define ll long long

#define ON_DEBUG

#ifdef ON_DEBUG

#define D_e_Line printf("\n\n----------\n\n")
#define D_e(x)  cout << #x << " = " << x << endl
#define Pause() system("pause")
#define FileOpen() freopen("in.txt","r",stdin);

#else

#define D_e_Line ;
#define D_e(x)  ;
#define Pause() ;
#define FileOpen() ;

#endif

struct ios{
    template<typename ATP>ios& operator >> (ATP &x){
        x = 0; int f = 1; char c;
        for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-')  f = -1;
        while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
        x*= f;
        return *this;
    }
}io;
using namespace std;

const int N = 500007;

int sum[N], endd[N], t[N][2], trieIndex;
char s[10007];
inline void Insert(char* str, int len){
	int rt = 0;
	R(i,1,len){
		int v = str[i] - '0';
		if(!t[rt][v]){
			t[rt][v] = ++trieIndex; // no return here
		}
		rt = t[rt][v];
		++sum[rt];
	}
	++endd[rt];
}
inline int Query(char *str, int len){
	int ans = 0;
	int rt = 0;
	int flag = false;
	R(i,1,len){
		int v = str[i] - '0';
		if(!t[rt][v]){
			flag = true;
			break;
		}
		rt = t[rt][v];  // let rt be t[rt][v] first, then add endd[rt]
		ans += endd[rt];
	}
	if(!flag) ans += sum[rt] - endd[rt]; // sum include endd
	return ans;
}

int main(){
//FileOpen();	

	int n, m;
    io >> n >> m;
    R(i,1,n){
    	int len;
        io >> len;
        R(j,1,len){
        	int x;
        	io >> x;
        	s[j] = x + '0';
        }
        Insert(s, len);
    }
    R(i,1,m){
    	int len;
        io >> len;
        R(j,1,len){
        	int x;
        	io >> x;
        	s[j] = x + '0';
        }
        printf("%d\n", Query(s, len));
    }
    
    return 0;
}
/*
4 5 
3 0 1 0 
1 1 
3 1 0 0 
3 1 1 0 
1 0 
1 1 
2 0 1 
5 0 1 0 0 1 
2 1 1 
*/