3.18
今天我们在网上找到了相关的视频讲解,是利用SQL语句的递归查询,听了视频的相关讲解,也算是理解了吧。
以一号线的王府井到二号线的积水潭为例
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
|
WITH RECURSIVE transfer (start_station, stop_station, stops, path) AS ( SELECT station_name, next_station, 1 , CAST(CONCAT(line_name,station_name , '->' , line_name,next_station) AS CHAR( 1000 )) FROM bj_subway WHERE station_name = '王府井' UNION ALL SELECT p.start_station, e.next_station, stops + 1 , CONCAT(p.path, '->' , e.line_name, e.next_station) FROM transfer p JOIN bj_subway e ON p.stop_station = e.station_name AND (INSTR(p.path, e.next_station) = 0 ) ) SELECT * FROM transfer WHERE stop_station = '积水潭' ; -- Oracle WITH transfer (start_station, stop_station, stops, path) AS ( SELECT station_name, next_station, 1 , line_name||station_name|| '->' ||line_name||next_station FROM bj_subway WHERE station_name = '王府井' UNION ALL SELECT p.start_station, e.next_station, stops + 1 , p.path|| '->' ||e.line_name||e.next_station FROM transfer p JOIN bj_subway e ON p.stop_station = e.station_name AND (INSTR(p.path, e.next_station) = 0 ) ) SELECT * FROM transfer WHERE stop_station = '积水潭' ; -- SQL Server WITH transfer(start_station, stop_station, stops, paths) AS ( SELECT station_name, next_station, 1 stops, CAST(concat(line_name,station_name, '->' ,line_name,next_station) AS varchar( 1000 )) AS paths FROM bj_subway WHERE station_name = '王府井' UNION ALL SELECT t.start_station, s.next_station, stops+ 1 , CAST(concat(paths, '->' , s.line_name, s.next_station) AS varchar( 1000 )) FROM transfer t JOIN bj_subway s ON (t.stop_station = s.station_name AND charindex(s.next_station, paths)= 0 ) ) SELECT * FROM transfer WHERE stop_station = '积水潭' ; -- PostgreSQL WITH RECURSIVE transfer (start_station, stop_station, stops, path) AS ( SELECT station_name, next_station, 1 , ARRAY[station_name::text, next_station::text] FROM bj_subway WHERE station_name = '王府井' UNION ALL SELECT p.start_station, e.next_station, stops + 1 , p.path || ARRAY[e.next_station::text] FROM transfer p JOIN bj_subway e ON p.stop_station = e.station_name AND NOT e.next_station = ANY(p.path) ) SELECT * FROM transfer WHERE stop_station = '积水潭' ; -- SQLite WITH RECURSIVE transfer(start_station, stop_station, stops, paths) AS ( SELECT station_name, next_station, 1 stops, line_name||station_name|| '->' ||line_name||next_station AS paths FROM bj_subway WHERE station_name = '王府井' UNION ALL SELECT t.start_station, s.next_station, stops+ 1 , paths|| '->' ||s.line_name||s.next_station FROM transfer t JOIN bj_subway s ON (t.stop_station = s.station_name AND instr(paths, s.next_station)= 0 ) ) SELECT * FROM transfer WHERE stop_station = '积水潭' ; Footer |
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· 震惊!C++程序真的从main开始吗?99%的程序员都答错了
· 【硬核科普】Trae如何「偷看」你的代码?零基础破解AI编程运行原理
· 单元测试从入门到精通
· 上周热点回顾(3.3-3.9)
· winform 绘制太阳,地球,月球 运作规律