关于hibernate查询映射时无法反序列化问题
org.springframework.orm.hibernate3.HibernateSystemException: could not deserialize; nested exception is org.hibernate.type.SerializationException: could not deserialize
以上是报错信息,网上查到的是说字段类型没有设置对应的类型,或者类型设置错误,这里根据我自己的实际情况,做一下补充情况
当在xml文件中设置字段的类型为枚举类型时,不能直接设置为枚举对象类,比如:
这样就不对了,无法解析,枚举类型应该要通过枚举类来解析,如下:
EnumUserType类如下:
package com.**.**.dao.usertype; import java.io.Serializable; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; import java.sql.Types; import org.hibernate.HibernateException; import org.hibernate.usertype.UserType; public class EnumUserType<E extends Enum<E>> implements UserType { private Class<E> clacz = null; protected EnumUserType(Class<E> c) { this.clacz = c; } private static final int[] SQL_TYPES = { Types.VARCHAR }; public int[] sqlTypes() { return SQL_TYPES; } public Class<E> returnedClass() { return clacz; } public Object nullSafeGet( ResultSet resultSet, String[] names, Object owner ) throws HibernateException, SQLException { String name = resultSet.getString( names[0] ); E result = null; if ( !resultSet.wasNull() ) { result = Enum.valueOf( clacz, name ); } return result; } public void nullSafeSet( PreparedStatement preparedStatement, Object value, int index ) throws HibernateException, SQLException { if ( null == value ) { preparedStatement.setNull( index, Types.VARCHAR ); } else { preparedStatement.setString( index, ((Enum<?>) value).name() ); } } public Object deepCopy( Object value ) throws HibernateException { return value; } public boolean isMutable() { return false; } public Object assemble( Serializable cached, Object owner ) throws HibernateException { return cached; } public Serializable disassemble( Object value ) throws HibernateException { return (Serializable) value; } public Object replace( Object original, Object target, Object owner ) throws HibernateException { return original; } public int hashCode( Object x ) throws HibernateException { return x.hashCode(); } public boolean equals( Object x, Object y ) throws HibernateException { if ( x == y ) return true; if ( null == x || null == y ) return false; return x.equals( y ); } }
以上仅是这类错误的一种原因,记录一下