Python for 循环每次取列表中指定个数元素

Outline

lis = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

从lis中每次取两个元素,且所取不重复:

[1, 2]
[3, 4]
[5, 6]
[7, 8]
[9, 10]

实现

method1

ret = []

a =  [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

for i in range(0,len(a), 2):
    ret.append(a[i:i+2])
    print(a[i:i+2])

# [1, 2]
# [3, 4]
# [5, 6]
# [7, 8]
# [9, 10]

method2

a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

for r in [a[i:i + 2] for i in range(0, len(a), 2)]:  # 列表生成式
    print(r)

# [1, 2]
# [3, 4]
# [5, 6]
# [7, 8]
# [9, 10]