mysql 获取当前月的第一天到昨日的所有日期

SELECT 
	ADDDATE(y.first, x.d - 1) as d
FROM
	(
	SELECT 1 AS d UNION ALL
	SELECT 2 UNION ALL
	SELECT 3 UNION ALL
	SELECT 4 UNION ALL
	SELECT 5 UNION ALL
	SELECT 6 UNION ALL
	SELECT 7 UNION ALL
	SELECT 8 UNION ALL
	SELECT 9 UNION ALL
	SELECT 10 UNION ALL
	SELECT 11 UNION ALL
	SELECT 12 UNION ALL
	SELECT 13 UNION ALL
	SELECT 14 UNION ALL
	SELECT 15 UNION ALL
	SELECT 16 UNION ALL
	SELECT 17 UNION ALL
	SELECT 18 UNION ALL
	SELECT 19 UNION ALL
	SELECT 20 UNION ALL
	SELECT 21 UNION ALL
	SELECT 22 UNION ALL
	SELECT 23 UNION ALL
	SELECT 24 UNION ALL
	SELECT 25 UNION ALL
	SELECT 26 UNION ALL
	SELECT 27 UNION ALL
	SELECT 28 UNION ALL
	SELECT 29 UNION ALL
	SELECT 30 UNION ALL
	SELECT 31
	) x,(SELECT CURDATE() - INTERVAL DAY(CURDATE()) - 1 DAY AS first, DAY(CURDATE())-1 AS yestoday) y
WHERE x.d <= y.yestoday



SQL是把X作为一张临时表(1-31号的穷举),通过Y获取年月日和昨日,关联查询出小于等于昨日的日期全部列举

posted @ 2018-03-28 15:02  Bug开发攻城狮  阅读(960)  评论(0编辑  收藏  举报