2020Python练习七——文件处理2
2020Python练习七——文件处理2
@2020.3.15
周末综合作业:
1、编写用户登录接口
#1、输入账号密码完成验证,验证通过后输出"登录成功"
#2、可以登录不同的用户
#3、同一账号输错三次锁定,(提示:锁定的用户存入文件中,这样才能保证程序关闭后,该用户仍然被锁定)
username1 = input('请输入你的名字:').strip() usercode1 = input('请输入你的密码:').strip() count=0 with open(r'D:\0tempt\db.txt',mode='rt',encoding='utf-8') as f: for line in f: #把用户输入的名字和密码与读出的内容作对比 username,usercode=line.strip('').split(':') if username1 == username and usercode1 == usercode: print('登录成功') break else: print('账号或密码错误,请重试') count+=1 else: print('账号或密码输错三次,账户已被锁定,请申请找回或修改密码') with open(r'D:\0tempt\clockeduser.txt',mode='wt',encoding='utf-8') as f: f.write('{}:{}'.format(username1,usercode1))
2、编写程序实现用户注册后,可以登录
提示:
while True:
msg = """
0 退出
1 登录
2 注册
"""
print(msg)
cmd = input('请输入命令编号>>: ').strip()
if not cmd.isdigit():
print('必须输入命令编号的数字,傻叉')
continue
if cmd == '0':
break
elif cmd == '1':
# 登录功能代码(附加:可以把之前的循环嵌套,三次输错退出引入过来)
pass
elif cmd == '2':
# 注册功能代码
pass
else:
print('输入的命令不存在')
while True:
msg = """
0 退出
1 登录
2 注册
"""
print(msg)
cmd = input('请输入命令编号>>: ').strip()
if not cmd.isdigit():
print('必须输入命令编号的数字,傻叉')
continue
if cmd == '0':
break
elif cmd == '1':
# 登录功能代码(附加:可以把之前的循环嵌套,三次输错退出引入过来)
count=0
with open(r'D:\0tempt\db.txt',mode='rt',encoding='utf-8') as f:
for line in f: #把用户输入的名字和密码与读出的内容作对比
username,usercode=line.strip('').split(':')
if username1 == username and usercode1 == usercode:
print('登录成功')
break
else:
print('账号或密码错误,请重试')
count+=1
else:
print('账号或密码输错三次,账户已被锁定,请申请找回或修改密码')
with open(r'D:\0tempt\clockeduser.txt',mode='wt',encoding='utf-8') as f:
f.write('{}:{}'.format(username1,usercode1))
elif cmd == '2':
# 注册功能代码
print("注册账号".center(40,"="))
info = {}
name = input("账号名:").strip()
pwd = input("账号密码:").strip()
# 读取文件中已存在的账号密码信息
with open("test1","r",encoding="utf-8") as f:
for line in f:
user_name, password = line.strip().split("-")
info[user_name] = password
else:
print('输入的命令不存在')
🐱不负韶华,只争朝夕🍚