流程控制

  • if
        var a = 3;
        if(a > 0){
          println(s"$a > 0")
        }else{
          println(s"$a < 0")
        }
        
    3 > 0

     

  • whilr
        var b = 3;
        while (b < 10){
          println(b)
          b += 1;
        }
        
    3
    4
    5
    6
    7
    8
    9

     

循环

  • 构造一个循环
        var one :Range.Inclusive = 1 to 10
        println(one)
        结果: Range(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
        
        var one :Range.Inclusive = 1 to (10, 2)
        println(one)
        结果: Range(1, 3, 5, 7, 9)
        
        var seqs = 1 until (10, 3)
        println(seqs)
        结果: Range(1, 4, 7)

     

  • 打印集合
        var seqs = 1 until 10
        for(i <- seqs){
          print(i)
        }
        结果: 123456789
        
        // 循环体没有break,有守卫
       var seqs = 1 until 10
        for(i <- seqs if(i % 2 == 0)){
          print(i)
        }
        结果:2468

     

  • 打印九九乘法表
        for(i <- 1 to 9){
          for(j <- 1 to 9){
            if(j<=i) print(s"$i * $j = ${i * j}\t")
            if(j == 1) println()
          }
        }
        
     简写:
        var num = 0;
         for(i <- 1 to 9; j <- 1 to 9){
             num += 1
            if(j<=i) print(s"$i * $j = ${i * j}\t")
            if(j == 1) println()
        }
        println(num)
        num 打印81次
        
     性能优化:
        var num = 0;
        for(i <- 1 to 9; j <- 1 to 9 if(j<=i)){
          num += 1
             print(s"$i * $j = ${i * j}\t")
            if(j == 1) println()
        }
        println(num)
        num 打印45次

     

  • 循环结果收集
        val ints = for(i <- 1 to 10) yield i
        println(ints)
        结果:Vector(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
      
        val ints = for(i <- 1 to 10) yield {
          val num = 2;
          i * num;
        }
        println(ints)
        结果: Vector(2, 4, 6, 8, 10, 12, 14, 16, 18, 20)

     

函数

  • 函数无返回值
        var y = fun01()
        def fun01(){
          println("fun001")
        }
        结果:fun001 函数要被调用才能打印
             ()  无结果返回

     

  • 函数有返回值,需要1.有定义
       def fun002(): Int ={
         3
       }
        var x = fun002();
        println(x)

     

  • 有参
        def fun03(a:Int): Unit ={
          println(a)
        }

     

  • 递归
        def fun04(num:Int): Int ={
          if(num == 1){
            num
          }else{
             num * fun04(num - 1)
          }
        }
        val i = fun04(4)
        println(i)
        
        结果: 24 
    return 4 * fun04(4 - 1)
    解析:
    fun04(4 - 1) = 3 * 2 * 1
    2 * fun04(2-1)
    fun04(2-1) = 1

     

  • 参数默认值
        def fun05 (a:Int = 10, b:String = "abc"): Unit ={
          println(s"$a\t$b")
        }
        fun05()
        结果:10    abc
        
        def fun05 (a:Int = 10, b:String = "abc"): Unit ={
          println(s"$a\t$b")
        }
        fun05(20)
        结果: 20 abc
        
        def fun05 (a:Int = 10, b:String = "abc"): Unit ={
          println(s"$a\t$b")
        }
        fun05(b = "wang")
        结果: 10    wang

     

  • 匿名函数
        var fun06 = (a:Int, b:Int) => {
          a + b
        }
        val str = fun06(3, 4)
        val str:Int = fun06(3, 4)
        println(str)
        结果:7
        
        var fun06:(Int, Int)=>Int   =   (a:Int, b:Int) =>{
          a + b
        }
        val str:Int = fun06(3, 4)
        println(str)
        结果:7
        
        (Int, Int) => Int (参数类型列表) => 返回值类型
        (a:Int, b:Int) => {a + b}     (参数实现列表) => 函数体

     

  • 嵌套函数
              方法里面套娃
  • 偏函数引用
        def fun07(date:Date, level:String, msg:String){
          println(s"date=$date\t tp=$level \t msg=$msg")
        }
        fun07(new Date(), "info", "MESSAGE")
        结果:date=Sat Jan 30 19:02:31 CST 2021     tp=info      msg=MESSAGE
        
        将日志级别恒定为error级别
        var fun = fun07(_:Date, "error", _:String)
        fun(new Date(), "exception...")
        结果: date=Sat Jan 30 19:03:56 CST 2021     tp=error      msg=exception...

     

  • 可变参数
        def fun08(a:Int*): Unit ={
          for(e <- a){
            println(e)
          }
        }
        fun08(5, 6 , 7)
        
        结果:
        5
        6
        7
        

     

  • forEach
        def fun08(a:Int*): Unit ={
          a.foreach( (x:Int)=> {
            println(x)
          })
        }
        fun08(5, 6 , 7)
        
        当有一个参数时候
        def fun08(a:Int*): Unit ={
          a.foreach( println(_))
        }
        fun08(5, 6 , 7)
        
        当有一个参数时候
        def fun08(a:Int*): Unit ={
          a.foreach( println)
        }
        fun08(5, 6 , 7)

     

 

高阶函数

  • 函数作为参数
        def computer(a:Int, b:Int, fun:(Int, Int) => Int): Unit ={
          var res: Int = fun(a , b)
          println(res)
        }
        computer(4, 5, (x:Int, y: Int)=>{ x * y})
        computer(4, 5, _+_)

     

  • 函数作为返回值
        def fun09(i: String): (Int, Int) => Int = {
          def plus(x: Int, y: Int): Int = {
            x + y
          }
          if (i.equals("+")) {
            plus
          } else {
            (x: Int, y: Int) => {
              x * y
            }
          }
        }
    
        computer(4, 5, fun09("+"))
        def computer(a: Int, b: Int, fun: (Int, Int) => Int): Unit = {
          var res: Int = fun(a, b)
          println(res)
        }
        结果: 9

     

  • 柯里化
        def fun10(a:Int)(b:Int)(c:String): Unit ={
          println(s"$a\t$b\t$c")
        }
        fun10(3)(8)("aa")
        结果:  3    8    aa
    
    
    应用: 一个可变参数想多个类型,可以拆成多个可变参数
        def fun11(a:Int*)(b:String*): Unit ={
          a.foreach(print)
          println()
          b.foreach(print)
        }
        fun11(1,2,3)("a","b","c")
        结果:
            123
            abc

     

  • 函数赋值

    def fun12(): Unit ={
    println("我是context")
    }
    val context = fun12
    println(context)
    val func = fun12 _ 这样写只有函数调用的时候才打印
    func()

     

    结果:

    我是context
    ()
    我是context

     

 

posted on 2021-01-31 12:40  陕西小楞娃  阅读(107)  评论(0编辑  收藏  举报