c++ 字符串转换为数字

#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <string.h>
#include <map>
//#include <sys/time.h>
using namespace std;
void main() {
    //定义map对象,当前没有任何元素
    map<char, int> m;

    //赋值:字符映射数字
    m['0'] = 0;
    m['1'] = 1;
    m['2'] = 2;
    m['3'] = 3;
    m['4'] = 4;
    m['5'] = 5;
    m['6'] = 6;
    m['7'] = 7;
    m['8'] = 8;
    m['9'] = 9;
    /**//*上面的10条赋值语句可采用下面这个循环简化代码编写
    for(int j = 0 ; j < 10 ; j++)
    {
            m['0' + j] = j ;
    }
    */
    string sa, sb;
    sa = "6234";
    int i;
    int sum = 0;
    int factor = 1;
    for (i = sa.length() - 1; i >= 0; i--) {

        if (i != sa.length() - 1) {
            factor *= 10;
        }

        sum += m[sa[i]] * factor;

    }
    cout << "sum = " << sum << endl;

}

 

posted @ 2020-08-04 10:37  Bigben  阅读(862)  评论(0编辑  收藏  举报