摘要: 女神的睿智 void solve() { string s; cin >> s; int a = 0, b = 0; for (int i = 0; i < s.size(); ++i) { if (s[i] == s[0]) a++; if (s[i] == s[4]) b++; } if (s[ 阅读全文
posted @ 2024-07-29 21:27 bible_w 阅读(36) 评论(0) 推荐(0) 编辑