摘要: A Many Formulas 思路:二进制枚举 void solve() { string s; cin >> s; int n = s.size(); int m = pow(2, n - 1); int ans = 0; for (int i = 0; i < m; ++i) { int no 阅读全文
posted @ 2024-07-22 20:36 bible_w 阅读(6) 评论(0) 推荐(0) 编辑