mysql查询今天、昨天、本周、本月、上一月 、今年数据
一下内容转载自:https://www.cnblogs.com/shuilangyizu/p/8805384.html
特在此记录一下。如有侵权,立刻联系删除。
--今天
select * from 表名 where to_days(时间字段名) = to_days(now());
--昨天
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1
--本周
SELECT * FROM 表名 WHERE YEARWEEK( date_format( 时间字段名,'%Y-%m-%d' ) ) = YEARWEEK( now() ) ;
--本月
SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) ,'%Y%m' )
--上一个月
SELECT * FROM 表名 WHERE PERIOD_DIFF(date_format(now(),'%Y%m'),date_format(时间字段名,'%Y%m') =1
--本年
SELECT * FROM 表名 WHERE YEAR( 时间字段名 ) = YEAR( NOW( ) )
--上一月
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1
--查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
--查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
--查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
--查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
--查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
--查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
--查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
--查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
--查询上个月的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
select *
from user
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select *
from [ user ]
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select *
from [ user ]
where pudate between 上月最后一天
and 下月第一天
where date(regdate) = curdate();
select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30
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