1、递归
本身调用自己,直到遇见不满足条件的阈值
斐波那契数列
li=[]
li[n]=li[n-1]+li[n-2]
def f(a1,a2):
a3=a1+a2
f(a2,a3)
posted on 2018-02-24 15:16 JuGooLar 阅读(80) 评论(0) 编辑 收藏 举报
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