求链表的中心节点
#include<iostream> using namespace std; class node{ public: node():value(0),next(NULL){} ~node(){} int value; node* next; };///be careful this ; node* createlist(int a[],int n) { node* startnode = new node[n]; node* ret = startnode; for(int i = 0;i<n;i++) { startnode[i].value = a[i]; if(i<n-1) startnode[i].next = startnode + i + 1; } while(startnode) { cout<<" "<<startnode->value; startnode = startnode->next; } cout<<endl; return ret; } void helper(node* head) { node* temp = head; while(head->next != NULL && head->next->next != NULL) { head = head->next->next; temp = temp->next; } cout<<temp->value; ///如果是奇数个,就是中间,如果是偶数个,指向第一个 } int main() { int a[] = {1,2,3,4,5,6,7,8,9}; node * t = createlist(a,8); helper(t); }
berkeleysong
posted on 2014-05-19 19:57 berkeleysong 阅读(170) 评论(0) 编辑 收藏 举报