链表的递归运算
#include<iostream> using namespace std; class node{ public: node():value(0),next(NULL){} ~node(){} int value; node* next; };///be careful this ; node* createlist(int a[],int n) { node* startnode = new node[n]; node* ret = startnode; for(int i = 0;i<n;i++) { startnode[i].value = a[i]; if(i<n-1) startnode[i].next = startnode + i + 1; } while(startnode) { cout<<" "<<startnode->value; startnode = startnode->next; } cout<<endl; return ret; } int helper(node* head) { if(head->next == NULL) return 1; else return helper(head->next) + 1; } int helper2(node* head) { if(head != NULL) { helper2(head->next); cout<<head->value<<" "; } } int main() { int a[] = {1,2,3,4,5,6,7,8,9}; node * t = createlist(a,9); cout<<helper(t); }
用的如此之多,希望能够慎重对待~!
berkeleysong
posted on 2014-05-19 19:43 berkeleysong 阅读(177) 评论(0) 编辑 收藏 举报