MySQL练习题及答案(复习)

新建一个叫做 review 的数据库,将测试数据脚本导进去。(可以使用Navicat查询功能)

/*
Navicat MySQL Data Transfer

Source Server         : DB
Source Server Version : 50723
Source Host           : localhost:3306
Source Database       : review

Target Server Type    : MYSQL
Target Server Version : 50723
File Encoding         : 65001

Date: 2019-02-25 23:48:25
*/

SET FOREIGN_KEY_CHECKS=0;

-- ----------------------------
-- Table structure for class
-- ----------------------------
DROP TABLE IF EXISTS `class`;
CREATE TABLE `class` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` char(4) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of class
-- ----------------------------
INSERT INTO `class` VALUES ('1', '高三1班');
INSERT INTO `class` VALUES ('2', '高三2班');
INSERT INTO `class` VALUES ('3', '高三3班');

-- ----------------------------
-- Table structure for course
-- ----------------------------
DROP TABLE IF EXISTS `course`;
CREATE TABLE `course` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` char(8) NOT NULL,
  `teacher_id` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `name` (`name`),
  KEY `fk_cou_tea` (`teacher_id`),
  CONSTRAINT `fk_cou_tea` FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of course
-- ----------------------------
INSERT INTO `course` VALUES ('1', 'python', '1');
INSERT INTO `course` VALUES ('2', 'java', '2');
INSERT INTO `course` VALUES ('3', 'php', '3');
INSERT INTO `course` VALUES ('4', 'c', '1');

-- ----------------------------
-- Table structure for score
-- ----------------------------
DROP TABLE IF EXISTS `score`;
CREATE TABLE `score` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `student_id` int(11) DEFAULT NULL,
  `course_id` int(11) DEFAULT NULL,
  `mark` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `fk_sco_stu` (`student_id`),
  KEY `fk_sco_cou` (`course_id`),
  CONSTRAINT `fk_sco_cou` FOREIGN KEY (`course_id`) REFERENCES `course` (`id`),
  CONSTRAINT `fk_sco_stu` FOREIGN KEY (`student_id`) REFERENCES `student` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=18 DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of score
-- ----------------------------
INSERT INTO `score` VALUES ('1', '1', '2', '79');
INSERT INTO `score` VALUES ('2', '2', '1', '58');
INSERT INTO `score` VALUES ('3', '2', '3', '66');
INSERT INTO `score` VALUES ('4', '2', '4', '80');
INSERT INTO `score` VALUES ('5', '3', '1', '63');
INSERT INTO `score` VALUES ('6', '3', '4', '95');
INSERT INTO `score` VALUES ('7', '4', '2', '88');
INSERT INTO `score` VALUES ('8', '4', '3', '62');
INSERT INTO `score` VALUES ('9', '5', '2', '59');
INSERT INTO `score` VALUES ('10', '5', '4', '100');
INSERT INTO `score` VALUES ('11', '1', '1', '55');
INSERT INTO `score` VALUES ('12', '3', '2', '81');
INSERT INTO `score` VALUES ('13', '4', '4', '50');
INSERT INTO `score` VALUES ('14', '5', '3', '77');
INSERT INTO `score` VALUES ('15', '1', '4', '58');
INSERT INTO `score` VALUES ('16', '1', '3', '91');
INSERT INTO `score` VALUES ('17', '6', '2', '75');

-- ----------------------------
-- Table structure for student
-- ----------------------------
DROP TABLE IF EXISTS `student`;
CREATE TABLE `student` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` char(2) NOT NULL,
  `gender` char(1) DEFAULT NULL,
  `class_id` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `fk_cou_cla` (`class_id`),
  CONSTRAINT `fk_cou_cla` FOREIGN KEY (`class_id`) REFERENCES `class` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of student
-- ----------------------------
INSERT INTO `student` VALUES ('1', '德玛', '', '1');
INSERT INTO `student` VALUES ('2', '妖姬', '', '2');
INSERT INTO `student` VALUES ('3', '盲僧', '', '3');
INSERT INTO `student` VALUES ('4', '蜘蛛', '', '1');
INSERT INTO `student` VALUES ('5', '卡牌', '', '2');
INSERT INTO `student` VALUES ('6', '露露', '', '3');

-- ----------------------------
-- Table structure for teacher
-- ----------------------------
DROP TABLE IF EXISTS `teacher`;
CREATE TABLE `teacher` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` char(2) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of teacher
-- ----------------------------
INSERT INTO `teacher` VALUES ('1', '佩奇');
INSERT INTO `teacher` VALUES ('2', '大熊');
INSERT INTO `teacher` VALUES ('3', '路飞');
测试数据脚本

数据表结构如下图:

练习题及答案如下:

-- 1、查询所有的课程的名称以及对应的任课老师姓名
select course.name as "课程",teacher.name as "任课老师" from course 
left join
teacher
on
course.teacher_id=teacher.id;

------------------------------------------------------------
-- 2、查询学习课程"python"比课程"java"成绩低的学生的学号
select python.student_id from
(select score.student_id,course.name,score.mark from score inner join course on score.course_id=course.id where course.name="python") as python
inner JOIN
(select score.student_id,course.name,score.mark from score inner join course on score.course_id=course.id where course.name="java") as java
on python.student_id=java.student_id
where python.mark<java.mark;

------------------------------------------------------------
-- 3、查询平均成绩大于65分的同学的id和平均成绩(保留两位小数)
select student_id,round(avg(mark),2) as m from score
group by student_id having m>65;

------------------------------------------------------------
-- 4、查询平均成绩大于65分的同学的姓名和平均成绩(保留两位小数);
select student.name,round(avg(mark),2) as m from score
inner join
student
on
score.student_id=student.id
group by student_id having m>65;

------------------------------------------------------------
-- 5、查询所有同学的姓名、选课数、总成绩
select student.name,count(score.course_id) as "选课数",sum(score.mark) as "总成绩" from score 
inner join
student
on
score.student_id=student.id
group by student_id;

------------------------------------------------------------
-- 6、查询没学过"路飞"老师课的同学的姓名
# 1)"路飞"老师任课的课程id
select course.id from course inner join teacher on course.teacher_id=teacher.id where teacher.name="路飞"
# 2)学过"路飞"老师的课的学生id
select score.student_id from score where score.course_id in
(select course.id from course inner join teacher on course.teacher_id=teacher.id where teacher.name="路飞")
group by score.student_id
# 3)最终结果
select student.name from student where id not in
(select score.student_id from score where score.course_id in
(select course.id from course inner join teacher on course.teacher_id=teacher.id where teacher.name="路飞")
group by score.student_id);

------------------------------------------------------------
-- 7、查询学过"python"并且也学过"java"课程的同学的姓名
select student.name from score 
left join student on score.student_id=student.id
where
score.course_id=(select id from course where name="python")
or
score.course_id=(select id from course where name="java")
group by score.student_id having count(1)>1;

------------------------------------------------------------
-- 8、查询学过"路飞"老师所教的全部课程的同学的姓名
select student.name from score inner join student on score.student_id=student.id where score.course_id in
(select course.id from course inner join teacher on course.teacher_id=teacher.id where teacher.name="路飞")
group by score.student_id;

-- 9、查询有课程成绩小于60分的同学的姓名
select name from student where id in
(select student_id from score where mark<60 group by student_id);

------------------------------------------------------------
-- 10、查询挂科超过两门(包括两门)的学生姓名
select name from student where id in
(select student_id from score where mark<60 group by student_id having count(1)>=2);
------------------------------------------------------------
-- 11、查询选修了全部课程的学生姓名
select name from student where id in
(select student_id from score group by student_id having count(1)=(select count(1) from course));

------------------------------------------------------------
-- 12、查询至少有一门课程与"卡牌"同学所学课程相同的同学姓名
select name from student where id in
(select student_id from score where course_id in
(select course_id from score inner join student on score.student_id=student.id where student.name="卡牌")
group by student_id)
and name!="卡牌";

------------------------------------------------------------
-- 13、查询学过"蜘蛛"同学全部课程的其他同学姓名
# 1)"蜘蛛"同学学过的课程id
select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛"
# 2)score表连student表,并筛选出课程id在("蜘蛛"同学学过的课程id),并且学生!="蜘蛛"
select student.name from score inner join student on score.student_id=student.id where score.course_id
in (select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
and student.name!="蜘蛛"
# 3)接着对结果进行分组,再次筛选得到最终结果
select student.name from score inner join student on score.student_id=student.id where score.course_id
in (select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
and student.name!="蜘蛛"
group by student_id
having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛");

------------------------------------------------------------
-- 14、查询和"蜘蛛"同学学习的课程完全相同的其他同学姓名;
# 1)找出与"蜘蛛"学习课程数相同的学生id(你学两门,我也学两门)
select * from score where score.student_id 
in
(select student_id from score 
group by score.student_id 
having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛"))
# 2)找出学过"蜘蛛"课程的学生,剩下的一定是至少学过一门"蜘蛛"课程的学生
select * from score where score.student_id 
in
(select student_id from score 
group by score.student_id 
having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛"))
and
score.course_id
in
(select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
# 3)根据学生id进行分组,剩下学生数count(1)=貂蝉学生所学课程数
select student_id from score where score.student_id 
in
(select student_id from score 
group by score.student_id 
having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛"))
and
score.course_id
in
(select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
group by
score.student_id
having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛")
and
score.student_id!=(select id from student where name="蜘蛛")
# 4)最终结果
select name from student where id in
(select student_id from score where score.student_id 
in
(select student_id from score 
group by score.student_id 
having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛"))
and
score.course_id
in
(select course_id from score inner join student on score.student_id=student.id where student.name="蜘蛛")
group by
score.student_id
having count(1)=(select count(1) from score inner join student on score.student_id=student.id where student.name="蜘蛛")
and
score.student_id!=(select id from student where name="蜘蛛"));

------------------------------------------------------------
-- 15、按平均成绩倒序显示所有学生的"python"、"java"、"php"三门的课程成绩,按如下形式显示: 学生id,python,java,php,课程数,平均分
# 1)先查询单一学生的python课程分数
select mark from score left join course on score.course_id = course.id where course.name = "python" and score.student_id=1;
# 2)将上面查询的结果作为列字段使用,得到最终结果
select student_id,
(select mark from score left join course on score.course_id = course.id where course.name = "python" and score.student_id=sc.student_id) as "python",
(select mark from score left join course on score.course_id = course.id where course.name = "java" and score.student_id=sc.student_id) as "java",
(select mark from score left join course on score.course_id = course.id where course.name = "php" and score.student_id=sc.student_id) as "php",
count(course_id) as "课程数",
avg(mark) as "平均分"
from score as sc
group by student_id order by avg(mark) desc;

------------------------------------------------------------
-- 16、查询各科成绩最高和最低的分:以如下形式显示:课程id,最高分,最低分
select course_id,max(mark) as "最高分",min(mark) as "最低分" from score group by course_id;

------------------------------------------------------------
-- 17、统计各科各分数段人数,显示格式:课程id,课程名称,[100-85],[85-70],[70-60],[<60]
select course_id,course.name,
sum(case when mark between 85 and 100 then 1 else 0 end) as "[100-85]",
sum(case when mark between 70 and 85 then 1 else 0 end) as "[85-70]",
sum(case when mark between 60 and 70 then 1 else 0 end) as "[70-60]",
sum(case when mark < 60 then 1 else 0 end) as "[<60]"
from score
inner join course
on score.course_id=course.id
GROUP BY score.course_id;

------------------------------------------------------------
-- 18、查询每门课程名字及其被选修的次数
select course.name,count(1) from score 
inner join course on score.course_id=course.id
group by course_id;

------------------------------------------------------------
-- 19、查询只选修了一门课程的学生的学号和姓名
select student_id,student.name from score
inner join student on score.student_id=student.id
group by student_id having count(course_id)=1;

------------------------------------------------------------
-- 20、查询学生表中男生、女生各有多少人
select
sum(case when gender="男" then 1 else 0 end) as "男生",
sum(case when gender="女" then 1 else 0 end) as "女生"
from student

------------------------------------------------------------
-- 21、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程id降序排列
select course.name,avg(mark) from score
inner join course on score.course_id=course.id
group by course_id
order by avg(mark) asc,course_id desc;

------------------------------------------------------------
-- 22、查询课程名称为"python"且分数低于60的学生姓名和分数
select student.name,mark from score
inner join student on score.student_id=student.id
where mark<60 and course_id=(select id from course where name="python");

------------------------------------------------------------
-- 23、求选了课程的学生人数
# 方式一:
select count(distinct student_id) from score;
# 方式二:
select count(1) from (select count(student_id) from score group by student_id) as a;

 

posted @ 2019-02-25 23:59  就俗人一个  阅读(4106)  评论(1编辑  收藏  举报