ip2Long 代码

def ip2Long(ip: String): Long = {
val fragments = ip.split("[.]")
var ipNum = 0L
for (i <- 0 until fragments.length) {
ipNum = fragments(i).toLong | ipNum << 8L
}
ipNum
}
posted @ 2018-10-17 11:29  BoomOoO  阅读(189)  评论(0编辑  收藏  举报