1026. Maximum Difference Between Node and Ancestor

Given the root of a binary tree, find the maximum value V for which there exists different nodes A and B where V = |A.val - B.val| and A is an ancestor of B.

(A node A is an ancestor of B if either: any child of A is equal to B, or any child of A is an ancestor of B.)

 

Example 1:

Input: [8,3,10,1,6,null,14,null,null,4,7,13]
Output: 7
Explanation: 
We have various ancestor-node differences, some of which are given below :
|8 - 3| = 5
|3 - 7| = 4
|8 - 1| = 7
|10 - 13| = 3
Among all possible differences, the maximum value of 7 is obtained by |8 - 1| = 7.

因为是比较最大 difference, 可以是正数，也可以是负数。

class Solution {
    public int maxAncestorDiff(TreeNode root) {
        int[] tempMax = { 0 };
        helper(root, root.val, root.val, tempMax);
        return tempMax[0];
    }
    
    public void helper(TreeNode root, int maxAncestor, int minAncestor, int[] tempMax) {
        if (root == null) return;
        tempMax[0] = Math.max(tempMax[0], Math.abs(maxAncestor - root.val));
        tempMax[0] = Math.max(tempMax[0], Math.abs(minAncestor - root.val));
        maxAncestor = Math.max(maxAncestor, root.val);
        minAncestor = Math.min(minAncestor, root.val);
        
        helper(root.left, maxAncestor, minAncestor, tempMax);
        helper(root.right, maxAncestor, minAncestor, tempMax);
    }
}