24 Game
You have 4 cards each containing a number from 1 to 9. You need to judge whether they could operated through *
, /
, +
, -
, (
, )
to get the value of 24.
Example 1:
Input: [4, 1, 8, 7] Output: True Explanation: (8-4) * (7-1) = 24
Example 2:
Input: [1, 2, 1, 2] Output: False
Note:
- The division operator
/
represents real division, not integer division. For example, 4 / (1 - 2/3) = 12. - Every operation done is between two numbers. In particular, we cannot use
-
as a unary operator. For example, with[1, 1, 1, 1]
as input, the expression-1 - 1 - 1 - 1
is not allowed. - You cannot concatenate numbers together. For example, if the input is
[1, 2, 1, 2]
, we cannot write this as 12 + 12.
思路:把每两个数拿出来,找出其所有的加减乘除组合,然后把每一个取出来,后剩余的两个数(总共也就是3个数),继续做同样的操作,直到只剩下一个数,看那个数是不是24.
1 class Solution { 2 public boolean judgePoint24(int[] nums) { 3 return helper(new double[] { nums[0], nums[1], nums[2], nums[3] }); 4 } 5 6 private boolean helper(double[] nums) { 7 if (nums.length == 1) return Math.abs(nums[0] - 24) < 0.01; 8 for (int i = 0; i < nums.length; i++) { 9 for (int j = i + 1; j < nums.length; j++) { 10 double[] remainings = new double[nums.length - 1]; 11 int idx = 0; 12 // add numbers in nums to remainings excluding nums[i] and nums[j] 13 for (int k = 0; k < nums.length; k++) { 14 if (k != i && k != j) { 15 remainings[idx] = nums[k]; 16 idx++; 17 } 18 } 19 for (double k : computeCombinations(nums[i], nums[j])) { 20 remainings[remainings.length - 1] = k; 21 if (helper(remainings)) { 22 return true; 23 } 24 } 25 } 26 } 27 return false; 28 } 29 30 private double[] computeCombinations(double a, double b) { 31 return new double[] { a + b, a - b, b - a, a * b, a / b, b / a }; 32 } 33 }