OpenFileDialog的使用实例

'Dim excelFolderPath As String = ""
'Dim openFileDialog1 As New OpenFileDialog()

'openFileDialog1.Filter = "Excel Files|*.xlsx;*.xls"
'openFileDialog1.Title = "Select Excel File"
'openFileDialog1.Multiselect = False

'If openFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then
' excelFolderPath = Path.GetDirectoryName(openFileDialog1.FileName)
'Else
' Return
'End If

posted @ 2023-05-18 09:12  侬侬发  阅读(27)  评论(0编辑  收藏  举报