Python获取当前时间、获取当月第一天、最后一天日期等方法


```python
先导入包:

import calendar
import datetime
from datetime import timedelta
获取今天日期:

#返回datetime格式:eg:2019-12-07 20:38:35.82816
now = datetime.datetime.now()

#返回datetime格式:eg:2019-12-07
now = datetime.datetime.now().date()
now = datetime.date.today()
获取昨天日期:

yesterday = now - timedelta(days=1)
获取明天日期:

tomorrow = now + timedelta(days=1)
获取本周第一天和最后一天:

this_week_start = now - timedelta(days=now.weekday())
this_week_end = now + timedelta(days=6-now.weekday())
获取上周第一天和最后一天:

last_week_start = now - timedelta(days=now.weekday()+7)
last_week_end = now - timedelta(days=now.weekday()+1)
获取本月第一天和最后一天:

this_month_start = datetime.datetime(now.year, now.month, 1)
this_month_end = datetime.datetime(now.year, now.month, calendar.monthrange(now.year, now.month)[1])
注:

calendar.monthrange(year,month)
传入两个值:一个是当前的年份,另外一个是当前的月份
写法可以是:calendar.monthrange(now.year,now.month)

返回两个整数。
第一个值为该月第一天所在的星期几,对应的数字。0 - 6==>0(星期一)到6(星期日)
第二个值为该月一共几天。

获取上月第一天和最后一天 :

last_month_end = this_month_start - timedelta(days=1)
last_month_start = datetime.datetime(last_month_end.year, last_month_end.month, 1)
获取本季第一天和最后一天:

month = (now.month - 1) - (now.month - 1) % 3 + 1
this_quarter_start = datetime.datetime(now.year, month, 1)
this_quarter_end = datetime.datetime(now.year, month, calendar.monthrange(now.year, now.month)[1])
获取上季第一天和最后一天:

last_quarter_end = this_quarter_start - timedelta(days=1)
last_quarter_start = datetime.datetime(last_quarter_end.year, last_quarter_end.month - 2, 1)
获取本年第一天和最后一天:

this_year_start = datetime.datetime(now.year, 1, 1)
this_year_end = datetime.datetime(now.year + 1, 1, 1) - timedelta(days=1)
获取去年第一天和最后一天:

last_year_end = this_year_start - timedelta(days=1)
last_year_start = datetime.datetime(last_year_end.year, 1, 1)


最后,如果要获取到date的格式,在最后加上".date"就能实现啦。

posted @ 2022-06-08 05:55  侬侬发  阅读(5610)  评论(0编辑  收藏  举报