摘要: 1,输入两个整数num1num2 计算它们的和差积商与余数。#includeint main(void){ double num1,num2; char op; printf("Type in an expression:"); scanf("%lf%c%lf",&num1,&op,&num2); if(op=='+') printf("=%.2f\n",num1+num2); else if(op=='-') printf("=%.2f\n",num1-nu 阅读全文
posted @ 2013-10-19 10:17 鲍。 阅读(169) 评论(1) 推荐(0) 编辑