#include <iostream>
#include<fstream>
using namespace std;
ifstream infile;
int main()
{
int a[10],b[10],c[10];
int noOfCase;
infile.open("1.txt");
void set(int [],int [],int []);
void standard(int [],int [],int []);
int meet(int,int,int,int);
void schedule(int [],int [],int []);
infile>>noOfCase;
int i = noOfCase;
while(noOfCase!=0)
{
set(a,b,c);
standard(a,b,c);
cout<<"Case "<<i-noOfCase+1<<": ";
schedule(a,b,c);
noOfCase--;
}
infile.close();
return 0;
}
void set(int a[],int b[],int c[])
{
for(int i=0;i<10;i++)
{
infile>>a[i];
}
for(int i=0;i<10;i++)
{
infile>>b[i];
}
for(int i=0;i<10;i++)
{
infile>>c[i];
}
/*for(int i=0;i<10;i++)
{
cout<<a[i]<<" ";
}
cout<<endl;
for(int i=0;i<10;i++)
{
cout<<b[i]<<" ";
}
cout<<endl;
for(int i=0;i<10;i++)
{
cout<<c[i]<<" ";
}
cout<<endl;*/
}
void standard(int a[],int b[],int c[])
{
for(int i=0;i<10;i++)
{
if(a[i]<6)
{
a[i]+=12;
}
if(b[i]<6)
{
b[i]+=12;
}
if(c[i]<6)
{
c[i]+=12;
}
}
/*for(int i=0;i<10;i++)
{
cout<<a[i]<<" ";
}
cout<<endl;
for(int i=0;i<10;i++)
{
cout<<b[i]<<" ";
}
cout<<endl;
for(int i=0;i<10;i++)
{
cout<<c[i]<<" ";
}*/
//cout<<endl;
}
int meet(int a,int b,int c,int d) //在编写这个函数时最好配合画图,把每一种情况用途裂化出来,不要漏掉任何一种情况
{
if(b<=c || d<=a)//a,b is seperate from c,d
{
return 0;
}
else if(c>=a && d<=b)//c,d are withwin a,b
{
return (d-c);
}
else if(c>=a && c<=b && d>=b)//overlap and c,d follow a,b
{
return (b-c);
}
else if(c<=a && d>=a && d<=b)//overlap and a,b follow c,d
{
return (d-a);
}
else//a>=c b<=d, that is, a,b are within c,d
{
return (b-a);
}
}
void schedule(int a[], int b[], int c[])
{
int hour[3] = {1,2,3};
int plan[3] = {-1};
int i = 0;
int j;
for (int n=0; n<3; n++)
{
j = 0;
for (; i<9; i=(i+2)%10, j++)//i=0,2,4,6,8
{
/*cout << "hour[n]" << hour[n] << endl;
cout << meet(a[i], a[i+1], b[i], b[i+1]) << endl;
cout << meet(b[i], b[i+1], c[i], c[i+1]) << endl;
cout << meet(a[i], a[i+1], c[i], c[i+1]) << endl;*/
if (meet(a[i], a[i+1], b[i], b[i+1])>=hour[n]&&
meet(b[i], b[i+1], c[i], c[i+1])>=hour[n]&&
meet(a[i], a[i+1], c[i], c[i+1])>=hour[n])
{
plan[n] = i/2;
//n++; //这里不用让n自增,因为跳出内层for循环后会执行外层循环中的n++
i=(i+2)%10;
break;
}
if (j == 4)
{
if (plan[n] == -1)//plan[n]=-1,没有安排时间,则说明不可安排
{
cout << "The meetings cannot be scheduled." << endl;
return;
}
}
}
}
switch (plan[0]+1)
{
case 1:cout<<"Monday";break;
case 2:cout<<"Tuesday";break;
case 3:cout<<"Wednesday";break;
case 4:cout<<"Thursday";break;
case 5:cout<<"Friday";
}
cout<<" for 1 hour,";
cout<<" then ";
switch (plan[1]+1)
{
case 1:cout<<"Monday";break;
case 2:cout<<"Tuesday";break;
case 3:cout<<"Wednesday";break;
case 4:cout<<"Thursday";break;
case 5:cout<<"Friday";
}
cout<<" for 2 hours,";
cout<<" then ";
switch (plan[2]+1)
{
case 1:cout<<"Monday";break;
case 2:cout<<"Tuesday";break;
case 3:cout<<"Wednesday";break;
case 4:cout<<"Thursday";break;
case 5:cout<<"Friday";
}
cout<<" for 3 hours."<<endl;
}