在多线程并发请求Api的场景中,如何控制每个线程的qps
想了一段时间,给出代码Demo
#include <stdio.h> #include <stdlib.h> #include <pthread.h> typedef struct qps_s{ int count; unsigned int second; }qps_t; pthread_key_t tdata; qps_t qps_data; int push_timestamp() { time_t tt; return time(&tt); } void *thread_data_del(void *tdata){ if(tdata){ free(tdata); printf("free\n"); } } void doing(){ qps_t *qps_data = (qps_t *)pthread_getspecific(tdata); //说明还没有设置过 if(!qps_data){ qps_data = (qps_t *)calloc(1, sizeof(qps_t)); qps_data->count = 0; qps_data->second = push_timestamp(); pthread_setspecific(tdata, qps_data); } while(1){ int now_time = push_timestamp(); if(now_time == qps_data->second){ //触发了qps限制 if(qps_data->count >= 2){ usleep(10000); continue; } //没有触发限制 else{ qps_data->count++; break; } }else{ //时间不相同,说明qps限制肯定没问题 qps_data->count = 1; qps_data->second = now_time; break; } } printf("request some api => %d, %d\n", qps_data->second, qps_data->count); } void *worker(void *argv){ int i; for(i = 0; i < 10; i++){ doing(); } } int main(){ pthread_t pid1, pid2; pthread_key_create(&tdata, (void *)(void *)thread_data_del); pthread_create(&pid1, NULL, worker, NULL); pthread_join(pid1, NULL); pthread_key_delete(tdata); return 0; }
效果
[work@dev news_push/]valgrind --tool=memcheck ./a.out ==31818== Memcheck, a memory error detector ==31818== Copyright (C) 2002-2013, and GNU GPL'd, by Julian Seward et al. ==31818== Using Valgrind-3.10.0 and LibVEX; rerun with -h for copyright info ==31818== Command: ./a.out ==31818== request some api => 1467205046, 1 request some api => 1467205046, 2 request some api => 1467205047, 1 request some api => 1467205047, 2 request some api => 1467205048, 1 request some api => 1467205048, 2 request some api => 1467205049, 1 request some api => 1467205049, 2 request some api => 1467205050, 1 request some api => 1467205050, 2 free ==31818== ==31818== HEAP SUMMARY: ==31818== in use at exit: 0 bytes in 0 blocks ==31818== total heap usage: 2 allocs, 2 frees, 280 bytes allocated ==31818== ==31818== All heap blocks were freed -- no leaks are possible ==31818== ==31818== For counts of detected and suppressed errors, rerun with: -v ==31818== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 2 from 2)
posted on 2016-06-29 21:04 bai_jimmy 阅读(1600) 评论(0) 编辑 收藏 举报