判断网页能否打开？python 

 1 #!/usr/bin/env python
 2 # coding=utf-8
 3 import requests
 4 
 5 headers = {
 6     "User-Agent": "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36"}
 7 
 8 with open('/Users/b1ancheng/Desktop/123.txt', 'r') as f:
 9     for line in f:
10         line = line.strip('\n').strip('\ufeff')
11         url = 'http://' + line
12         print(url)
13         try:
14             response= requests.get(url, headers=headers, timeout=5).status_code
15             print(response)
16             if response== 200:
17                 print('可打开')
18             else:
19                 print(response)
20         except Exception as e:
21                 with open('/Users/b1ancheng/Desktop/1.txt', 'a+') as f1:
22                     error = f1.write(line+'\n')
23                 print(e)

 针对批量判断http网站是否打开，如果为https，再跑一次。

posted @ 2017-10-15 15:23  编程好累啊!  阅读(4631)  评论(0)  编辑  收藏  举报