uva 10929 - You can say 11

 

 1 #include <cstdio>
 2 using namespace std;
 3 
 4 char in[1100];
 5 
 6 int main()
 7 {
 8     while(gets(in))
 9     {
10         if(in[0] == '0' && in[1] == 0) break;
11 
12         int s = 0;
13         for (int i = 0; in[i] != 0; i++)
14         {
15             s += (in[i] - '0');
16             s *= 10;
17             s %= 11;
18         }
19         printf(s == 0 ? "%s is a multiple of 11.\n" : "%s is not a multiple of 11.\n", in);
20     }
21     return 0;
22 }

 第二种思路不错，多想想！

 1 #include<iostream>
 2 #include<string>
 3 
 4 using namespace std;
 5 
 6 int main(){
 7     //freopen("in.txt","r",stdin);
 8     //freopen("out.txt","w",stdout);
 9 
10     char num[1001];
11 
12     int sum;
13 
14     while(1){
15         cin>>num;
16 
17         if(num[0]=='0' && strlen(num)==1) break;
18 
19         sum=0;
20 
21         for(int i=0;i<strlen(num);i+=2) sum+=num[i]-'0';
22         for(int i=1;i<strlen(num);i+=2) sum-=num[i]-'0';
23         cout << "sum: " << sum << endl;
24         if(sum%11==0) cout<<num<<" is a multiple of 11."<<endl;
25         else cout<<num<<" is not a multiple of 11."<<endl;
26     }
27 }

 

posted @ 2016-01-19 00:58  小小泽  阅读(239)  评论(0)  编辑  收藏  举报