摘要: String str = "8288822";char[] chars = str.toCharArray();Map<Character,Integer> map = new HashMap<>();for (char c : chars) { if (map.containsKey(c)){ m 阅读全文
posted @ 2021-11-09 18:07 暗影霹雳神 阅读(690) 评论(0) 推荐(0) 编辑