实验6
include <stdio.h>
include <string.h>
define N 2
typedef struct student {
int id;
char name[20];
char subject[20];
double perf;
double mid;
double final;
double total;
char level[10];
} STU;
void input(STU [], int);
void output(STU [], int);
void calc(STU [], int);
int fail(STU [], STU [], int);
void sort(STU [], int);
int main() {
STU st[N], fst[N];
int k;
printf("录入学生成绩信息:\n");
input(st, N);
printf("\n成绩处理...\n");
calc(st, N);
k = fail(st, fst, N);
sort(st, N);
printf("\n学生成绩排名情况:\n");
output(st, N);
printf("\n不及格学生信息:\n");
output(fst, k);
return 0;
}
void input(STU s[], int n) {
int i;
for(i = 0; i < n; i++)
scanf("%d %s %s %lf %lf %lf", &s[i].id, s[i].name, s[i].subject,
&s[i].perf, &s[i].mid, &s[i].final);
}
void output(STU s[], int n) {
int i;
printf("-----------------\n");
printf("学号 姓名 科目 平时 期中 期末 总评 等级\n");
for(i = 0; i<n; i++)
printf("%d %-6s %-4s %-4.0f %-4.0f %-4.0f %-4.1f %s\n",s[i].id,s[i].name,s[i].subject,s[i].perf,s[i].mid,s[i].final,s[i].total,s[i].level);
}
void calc(STU s[],int n) {
int i;
for(i = 0; i < n; i++) {
s[i].total = s[i].perf * 0.2 +
s[i].mid * 0.2 +
s[i].final * 0.6;
if(s[i].total >= 90)
strcpy(s[i].level, "优");
else if(s[i].total >= 80)
strcpy(s[i].level, "良");
else if(s[i].total >= 70)
strcpy(s[i].level, "中");
else if(s[i].total >= 60)
strcpy(s[i].level, "及格");
else
strcpy(s[i].level, "不及格");
}
}
int fail(STU s[], STU t[], int n) {
int i, cnt = 0;
for(i = 0; i < n; i++)
if(s[i].total < 60)
t[cnt++] = s[i];
return cnt;
}
void sort(STU s[], int n) {
int i, j;
STU t;
for(i = 0; i < n-1; i++)
for(j = 0; j < n-1-i; j++)
if(s[j].total < s[j+1].total) {
t = s[j];
s[j] = s[j+1];
s[j+1] = t;
}
}
任务4：
include <stdio.h>
define N 10
typedef struct {
char isbn[20];
char name[80];
char author[80];
double sales_price;
int sales_count;
} Book;
void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);
int main() {
Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
{"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
{"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
{"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
{"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
{"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
{"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
{"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
{"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
printf("图书销量排名(按销售册数): \n");
sort(x, N);
output(x, N);
printf("\n图书销售总额: %.2f\n", sales_amount(x, N));
return 0;
}
void output(Book x[], int n){
int i;
printf("isbn号 书名 作者 售价 销售册数\n") ;
for (i = 0; i < n; i++) {
printf("%-20s %-34s %-28s %-16.2f %d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
}
}
void sort(Book x[], int n){
int i,j;
Book t;
for(i=0;i<n-1;i++){
for(j=0;j<n-1-i;j++){
if(x[j].sales_count < x[j+1].sales_count){
t=x[j];
x[j]=x[j+1];
x[j+1]=t;
}
}
}
}
double sales_amount(Book x[], int n){
double sum=0;
int i;
for(i=0;i<n;i++){
sum+=x[i].sales_price * x[i].sales_count;
}
return sum;
}
任务5：
include <stdio.h>
typedef struct {
int year;
int month;
int day;
} Date;
void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);
void test1() {
Date d;
int i;
printf("输入日期:(以形如2024-12-16这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&d);
printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
}
}
void test2() {
Date Alice_birth, Bob_birth;
int i;
int ans;
printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n");
for(i = 0; i < 3; ++i) {
input(&Alice_birth);
input(&Bob_birth);
ans = compare_dates(Alice_birth, Bob_birth);
if(ans == 0)
printf("Alice和Bob一样大\n\n");
else if(ans == -1)
printf("Alice比Bob大\n\n");
else
printf("Alice比Bob小\n\n");
}
}
int main() {
printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
test1();
printf("\n测试2: 两个人年龄大小关系\n");
test2();
}
void input(Date *pd) {
scanf("%d-%d-%d", &(pd->year), &(pd->month), &(pd->day));
}
int day_of_year(Date d) {
int day=0,i;
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
if ((d.year % 4 == 0 && d.year % 100!= 0) || d.year % 400 == 0) {
a[1] = 29;
}else{
a[1] = 28;
}
for(i=0;i<d.month-1;i++){
day+=a[i];
}
day+=d.day;
return day;
}
int compare_dates(Date d1, Date d2) {
if (d1.year < d2.year) {
return -1;
} else if (d1.year > d2.year) {
return 1;
} else {
if (d1.month < d2.month) {
return -1;
} else if (d1.month > d2.month) {
return 1;
} else {
if (d1.day < d2.day) {
return -1;
} else if (d1.day > d2.day) {
return 1;
} else {
return 0;
}
}
}
}
任务6：
include <stdio.h>
include <string.h>
enum Role {admin, student, teacher};
typedef struct {
char username[20];
char password[20];
enum Role type;
} Account;
void output(Account x[], int n);
int main() {
Account x[] = {{"A1001", "123456", student},
{"A1002", "123abcdef", student},
{"A1009", "xyz12121", student},
{"X1009", "9213071x", admin},
{"C11553", "129dfg32k", teacher},
{"X3005", "921kfmg917", student}};
int n;
n = sizeof(x)/sizeof(Account);
output(x, n);
return 0;
}
void output(Account x[], int n) {
int i,j;
char m='*';
char a[7]="admin",s[7]="student",t[7]="teacher";
for (i = 0; i < n; i++) {
printf("%-10s", x[i].username);
int passwordLength = strlen(x[i].password);
for (j = 0; j < passwordLength-1; j++) {
printf("*");
}
printf("%-10c",m);
switch (x[i].type) {
case admin:
printf("%-10s\n",a);
break;
case student:
printf("%-10s\n",s);
break;
case teacher:
printf("%-10s\n",t);
break;
default:
break;
}
}
}
任务7：
include <stdio.h>
include <string.h>
typedef struct {
char name[20];
char phone[12];
int vip;
} Contact;
void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);
define N 10
int main() {
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt, i;
char name[20];
printf("显示原始通讯录信息: \n");
output(list, N);
printf("\n输入要设置的紧急联系人个数: ");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for(i = 0; i < vip_cnt; ++i) {
scanf("%s", name);
set_vip_contact(list, N, name);
}
printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
display(list, N);
return 0;
}
void set_vip_contact(Contact x[], int n, char name[]) {
int i;
for(i=0;i<n;i++){
if(strcmp(x[i].name,name)==0){
x[i].vip=1;
}
}
}
void display(Contact x[], int n) {
Contact temp;
int i,j;
for(i=0;i<n-1;i++){
for(j=0;j<n-i-1;j++){
if (x[j].vip < x[j + 1].vip) {
temp = x[j];
x[j] = x[j + 1];
x[j + 1] = temp;
} else if (x[j].vip == x[j + 1].vip && strcmp(x[j].name, x[j + 1].name) > 0) {
temp = x[j];
x[j] = x[j + 1];
x[j + 1] = temp;
}
}
}
output(x,n);
}
void output(Contact x[], int n) {
int i;
for(i = 0; i < n; ++i) {
printf("%-10s%-15s", x[i].name, x[i].phone);
if(x[i].vip)
printf("%5s", "*");
printf("\n");
}
}
