试验任务1

实验任务1

include<stdio.h>

int main()
{
printf(" O O\n");
printf(" \n");
printf("I I I I\n");

return 0;

}

include<stdio.h>

int main()
{
printf(" O\n");
printf("\n");
printf("I I\n");
printf(" O\n");
printf("\n");
printf("I I\n");

return 0;

}


实验任务2

include<stdio.h>

int main()
{
double a,b,c;
scanf("%lf%lf%lf",&a,&b,&c);
if(a + b > c && a + c > b && b + c > a)
printf("能构成三角形\n");
else
printf("不能构成三角形\n");
return 0;
}

实验任务3

include <stdio.h>

int main()
{
char ans1, ans2;
printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有,输入n或N表示没有) : ");
ans1 = getchar();
getchar();
printf("\n动手敲代码实践了没? (输入y或Y表示敲了,输入n或N表示木有敲) : ");
ans2 = getchar();
if (ans1 == 'y' && ans2 == 'y' || ans1 == 'Y' && ans2 == 'Y' || ans1 == 'y' && ans2 == 'Y' || ans1 == 'Y' && ans2 == 'y' )
printf("\n罗马不是一天建成的, 继续保持哦:)\n");
else
printf("\n罗马不是一天毁灭的, 我们来建设吧\n");
return 0;
}



实验任务4

include<stdio.h>

int main()
{
double x, y;
char c1, c2, c3;
int a1, a2, a3;

scanf("%d%d%d", &a1, &a2, &a3);
printf("a1 = %d, a2 = %d, a3 = %d\n", a1,a2,a3);

scanf("%c%c%c", &c1, &c2, &c3);
printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);

scanf("%lf%lf", &x, &y);
printf("x = %lf, y = %lf\n",x, y);
return 0;

}

实验任务5

include <stdio.h>

int main()
{
int year;
int yearSeconds = 60 * 60 * 24 * 365;
int totalSeconds = 1000000000;

year = totalSeconds / yearSeconds;

printf("10 亿秒约等于%d 年\n", year); 
return 0;

}

实验任务6

include <stdio.h>

include <math.h>

int main()
{
double x, ans;

scanf("%lf", &x);
ans = pow(x, 365);
printf("%.2f的365次方: %.2f\n", x, ans);
return 0;
}


include <stdio.h>

include <math.h>

int main()
{
double x, ans;

while(scanf("%lf", &x) != EOF)
{
ans = pow(x, 365);
printf("%.2f的365次方: %.2f\n", x, ans);
printf("\n");
}

return 0;

}

实验任务7

include <stdio.h>

int main()
{
double C,F;
while(scanf("%lf",&C) != EOF)
{
F = 1.8 * C + 32;
printf("摄氏度c = %.2f时,华氏度f = %.2f",C,F);
}

return 0;

}

实验任务8

include<stdio.h>

include<math.h>

int main()
{
double a,b,c,area,s,p;

while(scanf("%lf%lf%lf",&a,&b,&c) != EOF)
{
	s = (a + b + c) / 2;
    p= s*(s-a)*(s-b)*(s-c);
    area = sqrt(p);
	printf("a = %.2f,b = %.2f,c = %.2f,area = %.3f\n",a,b,c,area);
	printf("\n");
}

return 0;

}

posted @ 2024-09-25 17:00  安逸的氛围  阅读(2)  评论(0编辑  收藏  举报