C++对带有分隔符的字符串 分割为数字的通用解决方案

需求：

数据库取出的字段类似于 "1,3,4"

然后用数字处理后,，比如 "1,2,3" 再存回去

 

#include<stdio.h>
#include<string.h>


class MyStr{
public:
    //根据 "1,2,3" 获得数字数组
    static int *split(char * str,const char *split,const int count){
        if(strlen(str)==0 || strlen(split)==0)
            return NULL;
        if(count <=1) return NULL;
        int * ints=new int[count];
        memset(ints,0x0,count*sizeof(int));
        
        char split_str[48];
        int index_length=0;
        
        snprintf(split_str,48,"%%d%s",split);
        for (int i=0;i<count;i++){
            sscanf(str+index_length,split_str,&ints[i]);
            char num_str[20]={0};
            sprintf(num_str,"%d",ints[i]);
            index_length+=strlen(num_str)+strlen(split);
        }
        return ints;
    }
    //根据数字数组 组合为字符串
    static char * bindNumbersToStr(int * nums,const unsigned int  nums_length,const char * split){
        char * str=new char[1025];
        char num_str[20]={0};
        int index_length=0;
        for(int i=0;i<nums_length;i++){
            sprintf(str+index_length,"%d%s",nums[i],split);
            index_length=strlen(str);
        }
        str[index_length-strlen(split)]=0x0;
        return str;
    }
};

int main(){
    char str[]="1,3,5,7,9";
    int * ints=MyStr::split(str,",",5);
    for(int i=0;i<5;i++){
        printf("ints[%d]=%d\n",i,ints[i]);
    }
    
    
    char * s=MyStr::bindNumbersToStr(ints,5,";");
    printf("s=%s\n",s);
    delete s;
    delete ints;
    
    
    return 0;
}

运行结果：

ints[0]=1
ints[1]=3
ints[2]=5
ints[3]=7
ints[4]=9
s=1;3;5;7;9

如预期所料

当然还可以进一步完善。

 

 

 百度下，别人的方案：

http://zhidao.baidu.com/question/348273815.html

http://hi.baidu.com/hwygy_001/item/a073ff0d3eb743e4fe240d3b

 

http://www.cnblogs.com/huashanlin/archive/2011/04/25/2028597.html