Java 中使用Linq

 maven安装。

<dependency>
    <groupId>com.bestvike</groupId>
    <artifactId>linq</artifactId>
    <version>3.1.0</version>
</dependency>

带where查询

//方法链
var ddd = Linq.of(list).where(x -> x.getAge() > 15).toList();

//sql
String sql = "select * from user where age>15";

  简单的函数计算(max、min、count、sum)

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//方法链
//var ddd = Linq.of(list).max(x -> x.getAge());//获取最大的年龄
//var ddd = Linq.of(list).min(x -> x.getAge());//获取最小的年龄
//var ddd = Linq.of(list).count();//获取总数
var ddd = Linq.of(list).sumInt(x -> x.getAge());//获取总数

//sql
//String sql = "select max(age) from user";
//String sql = "select min(age) from user";
//String sql = "select count(1) from user";
String sql = "select sum(age) from user";
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  排序

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//方法链
//var ddd = Linq.of(list).orderBy(x -> x.getAge());//正序
var ddd = Linq.of(list).orderByDescending(x -> x.getAge());//倒序

//sql
//String sql = "select * from user order by age";
String sql = "select * from user order by age desc";
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  top1

//方法链
var ddd = Linq.of(list).firstOrDefault();

//sql
String sql = "select top 1 from user";

   跳过前面多少条数据,取剩下的数据

//方法链
var ddd = Linq.of(list).orderByDescending(x -> x.getAge()).skip(1);

//sql
String sql = "select * from (select ROW_NUMBER() over(order by age desc) as rowNum,*) t wher rowNum>1";

  分页查询

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//方法链
//跳过第一条,取两条,即取第二条到第四条
var ddd = Linq.of(list).orderByDescending(x -> x.getAge()).skip(1).take(3);

//sql
String sql = "select * from (select ROW_NUMBER() over(order by age desc) as rowNum,*) t wher rowNum>1 and rowNum<=4";
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  包含,相当于like

//方法链
var ddd = Linq.of(list).where(x->x.getName().contains("李"));

//sql
String sql = "select * from user where name like '%李%'";

  分组group by

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//方法链
var ddd = Linq.of(list).groupBy(x -> x.getAge()).toList();
for (var t : ddd) {
    System.out.println(t.getKey() + "--" + t.minInt(x -> x.getMoney()) + "--" + t.maxInt(x -> x.getMoney()) + "--" + t.sumInt(x -> x.getMoney()));
}

//sql
String sql = "select age,min(money),max(money),sum(money) from user group by age";
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  sql中的in

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//方法链
List<Integer> ages = new ArrayList<>();
ages.add(15);
ages.add(16);
var ddd = Linq.of(list).where(x -> ages.contains(x.getAge()));

//sql
String sql = "select * from user where age in (15,16)";

 

 
转自:https://www.cnblogs.com/shadoll/p/14292909.html
posted @ 2021-12-31 16:12  阿旭92312  阅读(2572)  评论(0编辑  收藏  举报