【最短路】【Heap-Dijkstra】【分层图】bzoj2662 [BeiJing wc2012]冻结
裸的分层图最短路。
1 #include<cstdio> 2 #include<cstring> 3 #include<queue> 4 #include<algorithm> 5 using namespace std; 6 #define N 51 7 #define K 51 8 #define M 2001 9 struct Point{int u,d;Point(const int &a,const int &b){d=a;u=b;}Point(){}}; 10 bool operator < (const Point &a,const Point &b){return a.d>b.d;} 11 priority_queue<Point>q; 12 int n,m,k,dis[N*K],ans=2147483647; 13 bool vis[N*K]; 14 int first[M*K*2],next[M*K*2],v[M*K*2],w[M*K*2],en,x,y,z; 15 void AddEdge(const int &U,const int &V,const int &W) 16 { 17 v[++en]=V; 18 w[en]=W; 19 next[en]=first[U]; 20 first[U]=en; 21 } 22 void dijkstra(const int &s) 23 { 24 memset(dis,0x7f,sizeof(dis)); 25 dis[s]=0; q.push(Point(0,s)); 26 while(!q.empty()) 27 { 28 Point x=q.top(); q.pop(); 29 if(!vis[x.u]) 30 { 31 vis[x.u]=0; 32 for(int i=first[x.u];i;i=next[i]) 33 if(dis[v[i]]>dis[x.u]+w[i]) 34 { 35 dis[v[i]]=dis[x.u]+w[i]; 36 q.push(Point(dis[v[i]],v[i])); 37 } 38 } 39 } 40 for(int i=0;i<=k;i++) ans=min(ans,dis[n+i*n]); 41 printf("%d\n",ans); 42 } 43 int main() 44 { 45 scanf("%d%d%d",&n,&m,&k); 46 for(int i=1;i<=m;i++) 47 { 48 scanf("%d%d%d",&x,&y,&z); 49 AddEdge(x,y,z); AddEdge(y,x,z); 50 for(int j=1;j<=k;j++) 51 { 52 AddEdge(x+j*n,y+j*n,z); 53 AddEdge(y+j*n,x+j*n,z); 54 AddEdge(x+(j-1)*n,y+j*n,z>>1); 55 AddEdge(y+(j-1)*n,x+j*n,z>>1); 56 } 57 } 58 dijkstra(1); 59 return 0; 60 }
——The Solution By AutSky_JadeK From UESTC
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