实验9:Problem F: 我们来做个Student类吧!

想要输出""的话:

cout<<"A student whose name is "<<"\""<<name<<"\""<<" and id is "<<id<<" is erased!"<<endl;
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Problem F: 我们来做个Student类吧!

Problem F: 我们来做个Student类吧!

Time Limit: 1 Sec  Memory Limit: 128 MB
Submit: 412  Solved: 215
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Description

请定义一个Student类,有4个属性:

1.char *name:姓名。

2.int numOfScores:课程数量

3.int *scores:所有课程的成绩。

4.int id:学生的编号。

只有3个方法:

1. 构造函数

2.析构函数

3.void Student::showStudent()方法:用于输出学生的信息。

请根据样例输出,写出该类的实现。

 

Input

输入分为多行。

第一行包含3个正整数M,N和P:其中M表明之后输入的测试用例数量;N表示每个人姓名的最大长度;P表示学生学习的课程的数量。

之后有M行,包含一个学生姓名(没有任何空白符)、P门课程的成绩。

 

Output

见样例。

注意:所有的输出两两之间用一个空格隔开,且每行输出的首尾都没有空格。

 

Sample Input

3 10 5 Tom 60 61 72 56 89 Jack 99 100 98 89 77 Mary 88 88 88 88 88

Sample Output

A student whose name is "Tom" and id is 1 is created! This student is "Tom" whose id is 1. This student's scores are: 60 61 72 56 89 A student whose name is "Tom" and id is 1 is erased! A student whose name is "Jack" and id is 2 is created! This student is "Jack" whose id is 2. This student's scores are: 99 100 98 89 77 A student whose name is "Jack" and id is 2 is erased! A student whose name is "Mary" and id is 3 is created! This student is "Mary" whose id is 3. This student's scores are: 88 88 88 88 88 A student whose name is "Mary" and id is 3 is erased!

HINT

 

Append Code

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#include<iostream>
using namespace std;
class Student{
public:
    char *name;
    int numOfScores;
    int *scores;
    static int id;
    Student(char *n,int *s,int num):name(n),scores(s),numOfScores(num){id++;cout<<"A student whose name is "<<"\""<<name<<"\""<<" and id is "<<id<<" is created!"<<endl;}
    ~Student(){cout<<"A student whose name is "<<"\""<<name<<"\""<<" and id is "<<id<<" is erased!"<<endl;}
    void showStudent()
    {
        cout<<"This student is "<<"\""<<name<<"\""<<" whose id is "<<id<<"."<<endl<<"This student's scores are:";
        for(int i=0;i<numOfScores;i++)
            cout<<" "<<scores[i];
        cout<<endl;
    }
};
int Student::id=0;
int main()
{
    int cases;
    char *str;
    int maxLenOfString, numOfCourses;
    int *scores;

    cin>>cases>>maxLenOfString>>numOfCourses;
    str = new char[maxLenOfString + 1];
    scores = new int[numOfCourses];
    for (int i = 0; i < cases; i++)
    {
        cin>>str;
        for (int j = 0; j < numOfCourses; j++)
            cin>>scores[j];
        Student stu(str,scores,numOfCourses);
        stu.showStudent();
    }
    return 0;
}

 

posted @ 2016-04-29 18:20  一一一匹马赛克儿  阅读(452)  评论(0编辑  收藏  举报