hdu 4893 线段树lazy wa代码 先放这里 我还会回来的!!
1 #include<iostream> 2 #include<stdio.h> 3 #include<cstring> 4 #include<cstdlib> 5 #include<queue> 6 #include<math.h> 7 #include<algorithm> 8 #include<vector> 9 #define maxx 100010 10 using namespace std; 11 #define ss __int64 12 13 struct node {int l,r;ss sum; bool flag;}; 14 node tree[maxx*4]; 15 ss f[100]; 16 17 void getfib() 18 { 19 f[0]=f[1]=1; 20 for(int i=2;i<=90;i++) 21 { 22 f[i]=f[i-1]+f[i-2]; 23 //printf("%I64d\n",f[i]); 24 } 25 } 26 27 int solve(ss x) //jiang x bian wei zui jin d fib 28 { 29 int l=0,r=90,best=0; 30 while(l<r) 31 { 32 int mid=(l+r)/2; 33 if(f[mid]<=x) 34 { 35 l=mid+1; 36 best=max(best,mid); 37 } 38 else 39 r=mid-1; 40 } 41 return best; 42 } 43 44 void build(int left,int right,int k) 45 { 46 int mid; 47 tree[k].l=left; 48 tree[k].r=right; 49 tree[k].sum=0; 50 tree[k].flag=false; 51 if(left==right) 52 return ; 53 mid=(left+right)/2; 54 build(left,mid,k*2); 55 build(mid+1,right,k*2+1); 56 } 57 58 void down(int k) 59 { 60 if(tree[k].flag==false) 61 return ; 62 tree[k].flag=false; 63 if(tree[k].l==tree[k].r) 64 { 65 66 int temp,a,b; 67 temp=solve(tree[k].sum); 68 printf("1----%d\n",tree[k].sum); 69 a=abs(tree[k].sum-f[temp]); 70 b=abs(tree[k].sum-f[temp+1]); 71 if(a<b) 72 { 73 tree[k].sum=f[temp]; 74 } 75 else if(a==b) 76 { 77 tree[k].sum=min(f[temp],f[temp+1]); 78 } 79 else 80 tree[k].sum=f[temp+1]; 81 printf("2------%d\n",tree[k].sum); 82 return ; 83 84 } 85 down(k*2); 86 down(k*2+1); 87 tree[k].sum=tree[k*2].sum+tree[k*2+1].sum; 88 } 89 90 int sum(int left,int right,int k) 91 { 92 if(tree[k].l==left&&tree[k].r==right) 93 { 94 if(tree[k].flag) 95 down(k); 96 return tree[k].sum; 97 } 98 int mid; 99 mid=(tree[k].l+tree[k].r)/2; 100 if(right<=mid) 101 return sum(left,right,k*2); 102 else if(left>=mid+1) 103 return sum(left,right,k*2+1); 104 else 105 return sum(left,mid,k*2)+sum(mid+1,right,k*2+1); 106 } 107 108 void add(int x,int zhi,int k) 109 { 110 if(tree[k].l==x&&x==tree[k].r) 111 { 112 if(tree[k].flag) 113 down(k); 114 tree[k].sum+=zhi; 115 return ; 116 } 117 int mid; 118 mid=(tree[k].l+tree[k].r)/2; 119 if(x<=mid) 120 add(x,zhi,k*2); 121 else 122 add(x,zhi,k*2+1); 123 tree[k].sum=tree[k*2].sum+tree[k*2+1].sum; 124 } 125 126 void biaoji(int left,int right,int k) 127 { 128 if(tree[k].l==left&&tree[k].r==right) 129 { 130 printf("biao %d %d\n",tree[k].l,tree[k].r); 131 tree[k].flag=true; 132 return ; 133 } 134 int mid; 135 mid=(tree[k].l+tree[k].r)/2; 136 if(right<=mid) 137 biaoji(left,right,k*2); 138 else if(left>=mid+1) 139 biaoji(left,right,k*2+1); 140 else 141 { 142 biaoji(left,mid,k*2); 143 biaoji(mid+1,right,k*2+1); 144 } 145 } 146 147 int main() 148 { 149 int i,j,n,m,a,b,c; 150 getfib(); 151 while(~scanf("%d%d",&n,&m)) 152 { 153 build(1,n,1); 154 while(m--) 155 { 156 scanf("%d%d%d",&a,&b,&c); 157 if(a==1) 158 add(b,c,1); 159 if(a==2) 160 printf("%d\n",sum(b,c,1)); 161 if(a==3) 162 biaoji(b,c,1); 163 } 164 } 165 return 0; 166 }