摘要: MYSQL: select de.dept_no,e.emp_no,s.salary from employees e join dept_emp de on e.emp_no=de.emp_no join salaries s on e.emp_no=s.emp_no where e.emp_no 阅读全文
posted @ 2021-10-12 22:49 Sempron2800+ 阅读(32) 评论(0) 推荐(0) 编辑
摘要: MYSQL: SELECT s.emp_no,Y.salary,Y.t_rank FROM (SELECT X.salary,CAST((@number := @number+1) AS SIGNED) AS t_rank FROM (SELECT DISTINCT salary FROM sala 阅读全文
posted @ 2021-10-12 20:37 Sempron2800+ 阅读(100) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select d.dept_no,d.dept_name,count(salary) as sum from departments d join dept_emp de on d.dept_no=de.dept_no join salaries s on de.emp_no=s.em 阅读全文
posted @ 2021-10-12 19:34 Sempron2800+ 阅读(117) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select last_name,first_name,dept_name from employees e left join dept_emp de on e.emp_no=de.emp_no left join departments d on d.dept_no=de.dept 阅读全文
posted @ 2021-10-12 15:34 Sempron2800+ 阅读(31) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select e.emp_no emp_no, s.salary salary, e.last_name last_name, e.first_name first_name from employees e join salaries s on e.emp_no = s.emp_no 阅读全文
posted @ 2021-10-12 15:29 Sempron2800+ 阅读(23) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select emp_no,salary from salaries order by salary desc limit 1,1; 阅读全文
posted @ 2021-10-12 15:03 Sempron2800+ 阅读(27) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select title,avg(salary) from titles join salaries on titles.emp_no=salaries.emp_no GROUP by title order by avg(salary); 阅读全文
posted @ 2021-10-12 11:37 Sempron2800+ 阅读(111) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select * from employees where MOD(emp_no, 2) = 1 and last_name != 'Mary' order by hire_date desc; 阅读全文
posted @ 2021-10-12 11:32 Sempron2800+ 阅读(47) 评论(0) 推荐(0) 编辑
摘要: MYSQL: SELECT X.dept_no,salaries.emp_no,X.maxSalary FROM salaries JOIN dept_emp ON salaries.emp_no=dept_emp.emp_no JOIN (SELECT dept_emp.dept_no,MAX(s 阅读全文
posted @ 2021-10-12 11:05 Sempron2800+ 阅读(44) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select dept_emp.emp_no,dept_manager.emp_no as manager from dept_emp join dept_manager on dept_emp.dept_no=dept_manager.dept_no where dept_emp.e 阅读全文
posted @ 2021-10-12 08:34 Sempron2800+ 阅读(34) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select emp_no from employees where emp_no not IN (select emp_no from dept_manager); 阅读全文
posted @ 2021-10-12 08:30 Sempron2800+ 阅读(26) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select DISTINCT salary from salaries order by salary desc; 阅读全文
posted @ 2021-10-12 08:27 Sempron2800+ 阅读(29) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select emp_no,count(*) from salaries group by emp_no having count(*) > 15; 阅读全文
posted @ 2021-10-12 08:23 Sempron2800+ 阅读(20) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select last_name,first_name,dept_no from employees left join dept_emp on employees.emp_no=dept_emp.emp_no; 阅读全文
posted @ 2021-10-12 08:18 Sempron2800+ 阅读(51) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select last_name,first_name,dept_no from employees join dept_emp on employees.emp_no=dept_emp.emp_no; 阅读全文
posted @ 2021-10-12 08:16 Sempron2800+ 阅读(31) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select salaries.*,dept_manager.dept_no from salaries join dept_manager on salaries.emp_no=dept_manager.emp_no order by salaries.emp_no; 阅读全文
posted @ 2021-10-12 08:11 Sempron2800+ 阅读(29) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select * from employees order by hire_date desc LIMIT 2,1; 阅读全文
posted @ 2021-10-12 08:06 Sempron2800+ 阅读(40) 评论(0) 推荐(0) 编辑
摘要: MYSQL: select * from employees order by hire_date desc LIMIT 0,1; 阅读全文
posted @ 2021-10-12 08:03 Sempron2800+ 阅读(44) 评论(0) 推荐(0) 编辑