摘要： 1 class Solution: 2 def converToBin(self,n): 3 N = [0] * 32 4 i = 31 5 while n != 0: 6 r = n % 2 7 N[i] = r 8 i -= 1 9 n = n // 2 10 return N 11 def m 阅读全文

摘要： 1 class Solution: 2 def isNonZeroNum(self,m): 3 s = str(m) 4 for i in range(len(s)): 5 if s[i] == '0': 6 return False 7 return True 8 9 def getNoZeroI 阅读全文