12 2018 档案
leetcode961
摘要:class Solution: def repeatedNTimes(self, A): doubleN = len(A) N = doubleN / 2 dic = {} for a in A: if a in dic.keys(): dic[a]=dic[a]+1 ... 阅读全文
posted @ 2018-12-23 16:22 Sempron2800+ 阅读(115) 评论(0) 推荐(0) 编辑
leetcode950
摘要:from queue import Queue class Solution: def deckRevealedIncreasing(self, deck): n = len(deck) que = Queue(maxsize=n) deck.sort() res = [0]*n for i in rang... 阅读全文
posted @ 2018-12-13 20:54 Sempron2800+ 阅读(132) 评论(0) 推荐(0) 编辑
leetcode938
摘要:class Solution: def __init__(self): self.li = [] def midSearch(self,node): if(node != None): self.midSearch(node.left) self.li.append(node.val) ... 阅读全文
posted @ 2018-12-13 10:50 Sempron2800+ 阅读(84) 评论(0) 推荐(0) 编辑
leetcode953
摘要:public class Solution { public bool IsAlienSorted(string[] words, string order) { string HumanDic = "abcdefghijklmnopqrstuvwxyz"; for (int i = 0; i x).ToA... 阅读全文
posted @ 2018-12-09 19:02 Sempron2800+ 阅读(119) 评论(0) 推荐(0) 编辑
leetcode949
摘要:这题又长又卵,没意思。 阅读全文
posted @ 2018-12-04 17:08 Sempron2800+ 阅读(132) 评论(0) 推荐(0) 编辑

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