C#版:

public class Solution {
    public string Convert(string s, int numRows) {
        char[] c = s.ToArray();
            int len = c.Length;
            StringBuilder[] sb = new StringBuilder[numRows];
            for (int i = 0; i < sb.Length; i++)
            {
                sb[i] = new StringBuilder();
            }
            int j = 0;
            while (j < len)
            {
                for (int idx = 0; idx < numRows && j < len; idx++) // vertically down
                    sb[idx].Append(c[j++]);
                for (int idx = numRows - 2; idx >= 1 && j < len; idx--) // obliquely up
                    sb[idx].Append(c[j++]);
            }
            for (int idx = 1; idx < sb.Length; idx++)
                sb[0].Append(sb[idx]);
            return sb[0].ToString();
    }
}

https://leetcode.com/problems/zigzag-conversion/#/description

 

Java版:

 1 class Solution {
 2     public String convert(String s, int numRows) {
 3         char[] c = s.toCharArray();
 4         int len = c.length;
 5         StringBuilder[] sBuilder = new StringBuilder[numRows];
 6         for (int i = 0; i < sBuilder.length; i++) {
 7             sBuilder[i] = new StringBuilder();
 8         }
 9         int j = 0;
10         while (j < len) {
11             for (int idx = 0; idx < numRows && j < len; idx++) {
12                 sBuilder[idx].append(c[j++]);
13             }
14             for (int idx = numRows - 2; idx >= 1 && j < len; idx--) {
15                 sBuilder[idx].append(c[j++]);
16             }
17         }
18         for (int idx = 1; idx < sBuilder.length; idx++) {
19             sBuilder[0].append(sBuilder[idx]);
20         }
21         return sBuilder[0].toString();
22     }
23 }

 

posted on 2017-05-06 18:35  Sempron2800+  阅读(129)  评论(0编辑  收藏  举报