public class Solution
    {
        public int MissingNumber(int[] nums)
        {
            var list = nums.OrderBy(x => x).ToList();

            var preNum = 0;

            foreach (var l in list)
            {
                if (l != preNum)
                {
                    return preNum;
                }
                preNum++;
            }
            return preNum;
        }
    }

https://leetcode.com/problems/missing-number/#/description

 

补充一个python的实现:

1 class Solution:
2     def missingNumber(self, nums):
3         missing = len(nums)
4         for i, num in enumerate(nums):
5             missing ^= i ^ num
6         return missing

不使用位运算特性:

 1 class Solution:
 2     def missingNumber(self, nums: List[int]) -> int:
 3         nums.sort()
 4         prenum = 0
 5         for x in nums:
 6             if x != prenum:
 7                 return prenum
 8             else:
 9                 prenum += 1
10         return prenum

 

posted on 2017-04-19 11:28  Sempron2800+  阅读(145)  评论(0编辑  收藏  举报