牛客SQL24--获取所有非manager员工当前的薪水情况

MYSQL:

select de.dept_no,e.emp_no,s.salary
from employees e join dept_emp de
on e.emp_no=de.emp_no
join salaries s
on e.emp_no=s.emp_no
where e.emp_no not IN
(select emp_no from dept_manager);