牛客SQL18--获取当前薪水第二多的员工的emp_no以及其对应的薪水salary

MYSQL:

select e.emp_no emp_no, s.salary salary, e.last_name last_name, e.first_name first_name
from employees e join salaries s 
on e.emp_no = s.emp_no
where s.salary =
(select max(s2.salary)
from salaries s2
where
s2.salary < (select max(salary) from salaries));