leetcode1344

class Solution:
    def angleClock(self, hour: int, minutes: int) -> float:
        m_angle = minutes * 6
        h_angle = (hour + minutes / 60) * 6 * 5 if hour != 12 else (minutes / 60) * 6 * 5
        diff = abs(m_angle - h_angle)
        diff = min(diff,360-diff)
        return diff

算法思路：先计算分针的角度。再计算时针的角度。取两个角度的差的绝对值，再取锐角。