leetcode1081

找到一个跟我的思路比较接近的参考解决方案：

 1 class Solution:
 2     def smallestSubsequence(self, text: str) -> str:
 3         n = len(text)
 4         d = collections.defaultdict(collections.deque)
 5         # record index
 6         for i,v in enumerate(text):
 7             d[ord(v)-ord('a')].append(i)
 8         
 9         # search orderly
10         keys = sorted(d.keys())
11         res = []
12         c = len(d)
13         last_index = -1
14         while len(res) < c: # len(res) will not larger than 26
15             # O(26*26) time, search the first smallest letter
16             for i in range(len(keys)):
17                 if all(d[keys[i]][0] < d[keys[j]][-1] for j in range(i+1, len(keys))):
18                     res.append(chr(ord('a')+keys[i]))
19                     last_index = d[keys[i]][0]
20                     keys.remove(keys[i])
21                     break
22             # O(n) time, delete all index less than last_index
23             for i in range(len(keys)):
24                 while d[keys[i]] and d[keys[i]][0] < last_index:
25                     d[keys[i]].popleft()
26   
27         return ''.join(res)

参考：https://leetcode.com/problems/smallest-subsequence-of-distinct-characters/discuss/308222/show-my-thinking-process

posted on 2019-06-09 21:53 Sempron2800+ 阅读(148) 评论(0) 编辑收藏举报