这道题暴力算法,会超时:

1 class Solution(object):
2     def maxScoreSightseeingPair(self, A: 'List[int]') -> int:
3         n = len(A)
4         maxsum = 0
5         for i in range(n):
6             for j in range(i+1,n):
7                 cursum = A[i] + A[j] + i - j
8                 maxsum = max(maxsum,cursum)
9         return maxsum

因此,需要使用动态规划解决:

1 class Solution(object):
2     def maxScoreSightseeingPair(self, A: 'List[int]') -> int:
3         n = len(A)
4         ans = 0
5         pre = A[0]
6         for i in range(1,n):
7             pre = max(pre,A[i-1]+i-1)
8             ans = max(ans,A[i]+pre-i)
9         return ans

参考:https://leetcode.com/problems/best-sightseeing-pair/discuss/261041/easy-understand-one-pass-answer-by

posted on 2019-03-24 15:00  Sempron2800+  阅读(218)  评论(0编辑  收藏  举报