1 class Solution {
 2     public List<String> removeInvalidParentheses(String s) {
 3         List<String> ans = new ArrayList<>();
 4         remove(s, ans, 0, 0, new char[]{'(', ')'});
 5         return ans;
 6     }
 7 
 8     public void remove(String s, List<String> ans, int last_i, int last_j,  char[] par) {
 9         for (int stack = 0, i = last_i; i < s.length(); ++i) {
10             if (s.charAt(i) == par[0]) stack++;
11             if (s.charAt(i) == par[1]) stack--;
12             if (stack >= 0) continue;
13             for (int j = last_j; j <= i; ++j)
14                 if (s.charAt(j) == par[1] && (j == last_j || s.charAt(j - 1) != par[1]))
15                     remove(s.substring(0, j) + s.substring(j + 1, s.length()), ans, i, j, par);
16             return;
17         }
18         String reversed = new StringBuilder(s).reverse().toString();
19         if (par[0] == '(') // finished left to right
20             remove(reversed, ans, 0, 0, new char[]{')', '('});
21         else // finished right to left
22             ans.add(reversed);
23     }
24 }

参考:https://leetcode.com/problems/remove-invalid-parentheses/discuss/75027/Easy-Short-Concise-and-Fast-Java-DFS-3-ms-solution

posted on 2019-03-07 11:01  Sempron2800+  阅读(171)  评论(0编辑  收藏  举报