SQL Server(四)——查询练习(45道习题)转
题目:设有一数据库,包括四个表:学生表(Student)、课程表(Course)、成绩表(Score)以及教师信息表(Teacher)。
四个表的结构分别如表1-1的表(一)~表(四)所示,数据如表1-2的表(一)~表(四)所示。用SQL语句创建四个表并完成相关题目。
表1-1数据库的表结构
表(一)Student (学生表)
属性名 |
数据类型 |
可否为空 |
含 义 |
Sno |
varchar (20) |
否 |
学号(主码) |
Sname |
varchar (20) |
否 |
学生姓名 |
Ssex |
varchar (20) |
否 |
学生性别 |
Sbirthday |
datetime |
可 |
学生出生年月 |
Class |
varchar (20) |
可 |
学生所在班级 |
表(二)Course(课程表)
属性名 |
数据类型 |
可否为空 |
含 义 |
Cno |
varchar (20) |
否 |
课程号(主码) |
Cname |
varchar (20) |
否 |
课程名称 |
Tno |
varchar (20) |
否 |
教工编号(外码) |
表(三)Score(成绩表)
属性名 |
数据类型 |
可否为空 |
含 义 |
Sno |
varchar (20) |
否 |
学号(外码) |
Cno |
varchar (20) |
否 |
课程号(外码) |
Degree |
Decimal(4,1) |
可 |
成绩 |
主码: |
表(四)Teacher(教师表)
属性名 |
数据类型 |
可否为空 |
含 义 |
Tno |
varchar (20) |
否 |
教工编号(主码) |
Tname |
varchar (20) |
否 |
教工姓名 |
Tsex |
varchar (20) |
否 |
教工性别 |
Tbirthday |
datetime |
可 |
教工出生年月 |
Prof |
varchar (20) |
可 |
职称 |
Depart |
varchar (20) |
否 |
教工所在部门 |
表1-2数据库中的数据
表(一)Student
Sno |
Sname |
Ssex |
Sbirthday |
class |
108 |
曾华 |
男 |
1977-09-01 |
95033 |
105 |
匡明 |
男 |
1975-10-02 |
95031 |
107 |
王丽 |
女 |
1976-01-23 |
95033 |
101 |
李军 |
男 |
1976-02-20 |
95033 |
109 |
王芳 |
女 |
1975-02-10 |
95031 |
103 |
陆君 |
男 |
1974-06-03 |
95031 |
表(二)Course
Cno |
Cname |
Tno |
3-105 |
计算机导论 |
825 |
3-245 |
操作系统 |
804 |
6-166 |
数字电路 |
856 |
9-888 |
高等数学 |
831 |
表(三)Score
Sno |
Cno |
Degree |
103 |
3-245 |
86 |
105 |
3-245 |
75 |
109 |
3-245 |
68 |
103 |
3-105 |
92 |
105 |
3-105 |
88 |
109 |
3-105 |
76 |
101 |
3-105 |
64 |
107 |
3-105 |
91 |
108 |
3-105 |
78 |
101 |
6-166 |
85 |
107 |
6-166 |
79 |
108 |
6-166 |
81 |
表(四)Teacher
Tno |
Tname |
Tsex |
Tbirthday |
Prof |
Depart |
804 |
李诚 |
男 |
1958-12-02 |
副教授 |
计算机系 |
856 |
张旭 |
男 |
1969-03-12 |
讲师 |
电子工程系 |
825 |
王萍 |
女 |
1972-05-05 |
助教 |
计算机系 |
831 |
刘冰 |
女 |
1977-08-14 |
助教 |
电子工程系 |
查询问题:
1、 查询Student表中的所有记录的Sname、Ssex和Class列。
2、 查询教师所有的单位即不重复的Depart列。
3、 查询Student表的所有记录。
4、 查询Score表中成绩在60到80之间的所有记录。
5、 查询Score表中成绩为85,86或88的记录。
6、 查询Student表中“95031”班或性别为“女”的同学记录。
7、 以Class降序查询Student表的所有记录。
8、 以Cno升序、Degree降序查询Score表的所有记录。
9、 查询“95031”班的学生人数。
10、 查询Score表中的最高分的学生学号和课程号。(子查询或者排序)
11、 查询每门课的平均成绩。
12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。
13、查询分数大于70,小于90的Sno列。
14、查询所有学生的Sname、Cno和Degree列。
15、查询所有学生的Sno、Cname和Degree列。
16、查询所有学生的Sname、Cname和Degree列
17、 查询“95033”班学生的平均分。
18、 假设使用如下命令建立了一个grade表:
create table grade(low int,upp int,rank char(1))
insert into grade values(90,100,’A’)
insert into grade values(80,89,’B’)
insert into grade values(70,79,’C’)
insert into grade values(60,69,’D’)
insert into grade values(0,59,’E’)
现查询所有同学的Sno、Cno和rank列。
19、 查询选修“3-105”课程的成绩高于“109”号同学成绩的所有同学的记录。
20、查询score中选学多门课程的同学中分数为非最高分成绩的记录。
21、查询成绩高于学号为“109”、课程号为“3-105”的成绩的所有记录。
22、查询和学号为108的同学同年出生的所有学生的Sno、Sname和Sbirthday列。
23、查询“张旭“教师任课的学生成绩。
24、查询选修某课程的同学人数多于5人的教师姓名。
25、查询95033班和95031班全体学生的记录。
26、 查询存在有85分以上成绩的课程Cno.
27、查询出“计算机系“教师所教课程的成绩表。
28、查询“计算机系”与“电子工程系“不同职称的教师的Tname和Prof。
29、查询选修编号为“3-105“课程且成绩至少高于选修编号为“3-245”的同学的Cno、Sno和Degree,并按Degree从高到低次序排序。
30、查询选修编号为“3-105”且成绩高于选修编号为“3-245”课程的同学的Cno、Sno和Degree.
31、 查询所有教师和同学的name、sex和birthday.
32、查询所有“女”教师和“女”同学的name、sex和birthday.
33、 查询成绩比该课程平均成绩低的同学的成绩表。
34、 查询所有任课教师的Tname和Depart.
35 、 查询所有未讲课的教师的Tname和Depart.
36、查询至少有2名男生的班号。
37、查询Student表中不姓“王”的同学记录。
38、查询Student表中每个学生的姓名和年龄。
39、查询Student表中最大和最小的Sbirthday日期值。
40、以班号和年龄从大到小的顺序查询Student表中的全部记录。
41、查询“男”教师及其所上的课程。
42、查询最高分同学的Sno、Cno和Degree列。
43、查询和“李军”同性别的所有同学的Sname.
44、查询和“李军”同性别并同班的同学Sname.
45、查询所有选修“计算机导论”课程的“男”同学的成绩表。
create database xuesheng
use xuesheng
go
create table Student
(
Sno varchar(20) not null primary key,
Sname varchar(20) not null,
Ssex varchar(20) not null,
Sbirthday datetime,
Class varchar(20)
)
go
create table Teacher
(
Tno varchar(20) not null primary key,
Tname varchar(20) not null,
Tsex varchar(20) not null,
Tbrithday datetime,
Prof varchar(20),
Depart varchar(20) not null
)
go
create table Course
(
Cno varchar(20) not null primary key,
Cname varchar(20) not null,
Tno varchar(20) not null references Teacher(Tno)
)
go
create table Score
(
Sno varchar(20) not null references Student(Sno),
Cno varchar(20) not null references Course(Cno),
Degree Decimal(4,1)
)
alter table Score add constraint pk primary key(Sno, Cno)
1、select Sname , Ssex , Class from Student 2、select distinct Depart from Teacher ——去重查询 3、select * from Student 4、select * from Score where Degree between 60 and 80 ——范围查询,between关键字 5、select * from Score where Degree=85 or Degree=86 or Degree=88 select * from Score where Degree in(85,86,88) 6、select * from Student where Ssex='女' or Class=95031 ——条件查询 7、select * from Student order by Class desc 8、select * from Score order by Cno asc,Degree desc ——排序查询 9、select count(*) from Student where Class=95031 10、select Sno,Cno from score where Degree=(select MAX(Degree) from score)——运用子查询 11、select cno ,AVG(Degree) from Score group by Cno 12、select Cno,avg(Degree) from score group by Cno having count(Sno)>=5 and Cno like '3%' ——分组查询与模糊查询 (师)select Cno,avg(Degree) from score where Cno like '3%' group by Cno having count(Sno)>=5 ——聚合函数 count 13、select Sno from Score where Degree between 70 and 90 14、select Sname,Cno,degree from student,score where student.Sno=score.Sno (师)select Sname,Cno,degree from score join student on score.sno=student.sno ——连接查询,join on 15、select Sno,Cname,degree from course,score where course.cno=score.cno (师)select Sname,Cno,degree from score join course on score.cno=course.cno 16、select Sname,Cname,degree from student, course,score where student.Sno=score.Sno and course.cno=score.cno (师)select Sname,Cno,degree from score join student on score.sno=student.sno join course on score.cno=course.cno 17、select avg(degree) from score where sno in (select sno from student where class='95033') ——离散查询 18、select Sno,Cno,rank from score,grade where score.degree between low and upp 19、select * from score where cno='3-105' and degree>(select degree from score where sno='109'and cno='3-105')——第一种理解 select * from score where cno='3-105' and degree>(select max(degree) from score where sno='109')——理解二 20、select * from score b where degree <(select max(degree) from score a where a.cno=b.cno) select * from score where degree not in (select max(degree) from score group by cno having count(sno)>1) (师)select * from score where sno in (select sno from score group by sno having count(*)>1) and degree <(select max(degree) from score ) select * from score a where sno in (select sno from score group by sno having count(*)>1) and degree <(select max(degree) from score b where b.cno=a.cno ) 21、select * from score where cno='3-105' and degree>(select degree from score where sno='109'and cno='3-105') 22、select sno,sname,sbirthday from student where datediff(year,sbirthday,getdate())=(select datediff(year,sbirthday,getdate()) from student where sno='108') select * from student where year(sbirthdy)=(select year(sbirthday) from student where sno='108') 23、select cno,sno,degree from score where cno=(select cno from course ,teacher where course.tno=teacher.tno and teacher.tname='张旭') (师)select * from score where cno in(select cno from course where tno in(select tno from teacher where tname='张旭')) 24、select tname from teacher where tno in (select tno from course where cno in (select cno from score group by cno having count(*)>5)) 25、select * from student where class in('95033','95031')或者select * from student where class ='95033'or class='95031' 26、select distinct cno from score where degree>85 27、select cno,sno,degree from score where cno in (select cno from course ,teacher where course.tno=teacher.tno and teacher.depart='计算机系') (师)select * from score where cno in(select cno from course where tno in(select tno from teacher where depart='计算机系')) 28、select tname,prof from teacher where depart='计算机系' and prof not in (select prof from teacher where depart='电子工程系') union select tname,prof from teacher where depart='电子工程系' and prof not in (select prof from teacher where depart='计算机系') select tname,prof from teacher a where prof not in (select prof from teacher b where b.depart != a.depart) 29、select * from score where cno='3-105' and degree>any (select degree from score where cno='3-245')order by degree desc——any其中任何一个、all所有 30、select * from score where cno='3-105' and degree>(select max(degree) from score where cno='3-245') 31、select tname,tsex,tbirthday from teacher union select sname,ssex,sbirthday from student 32、select tname,tsex,tbirthday from teacher where tsex='女' union select sname,ssex,sbirthday from student where ssex='女' 33、select * from score a where degree<(select avg(degree)from score b where a.cno=b.cno) 34、select tname,depart from teacher a where exists(select * from course b where a.tno=b.tno); select tname,depart from teacher,course where Teacher.tno=Course.tno (师)select tname,depart from teacher where tno in( select tno from course where cno in( select distinct cno from score)) 35、select tname,depart from teacher a where not exists(select * from course b where a.tno=b.tno); (师)select tname,depart from teacher where tno not in( select tno from course where cno in( select distinct cno from score)) 36、select class from student where ssex='男'group by class having count(*)>=2; 37、 select * from student where sname not like'王%'; 38、select sname as 姓名,datediff(year,sbirthday,getdate()) as 年龄 from student select sname as 姓名,year(getdate())-year(sbirthday) as 年龄 from student 39、select sname,sbirthday as 最大 from student where sbirthday =(select min (sbirthday) from student) union select sname,sbirthday as 最小 from student where sbirthday =(select max(sbirthday) from student) (师)select min (sbirthday),max(sbirthday) from student 40、select class,sname,sbirthday from student order by class desc,sbirthday; 41、select x.tname,y.cname from teacher x,course y where x.tno=y.tno and x.tsex='男'; select tname,cname from teacher ,course where teacher.tno=course.tno and tsex='男' 42、select * from score where degree=(select max(degree)from score); (师)selsct top 1 * from score order by degree desc——只适用于有一个最高分 43、select sname from student where ssex=(select ssex from student where sname='李军'); 44、select sname from student where ssex=(select ssex from student where sname='李军') and class=(select class from student where sname='李军'); 45、select * from score where sno in(select sno from student where ssex='男') and cno=(select cno from course where cname='计算机导论');
1、select Sname , Ssex , Class from Student 2、select distinct Depart from Teacher ——去重查询 3、select * from Student 4、select * from Score where Degree between 60 and 80 ——范围查询,between关键字 5、select * from Score where Degree=85 or Degree=86 or Degree=88 select * from Score where Degree in(85,86,88) 6、select * from Student where Ssex='女' or Class=95031 ——条件查询 7、select * from Student order by Class desc 8、select * from Score order by Cno asc,Degree desc ——排序查询 9、select count(*) from Student where Class=95031 10、select Sno,Cno from score where Degree=(select MAX(Degree) from score)——运用子查询 11、select cno ,AVG(Degree) from Score group by Cno 12、select Cno,avg(Degree) from score group by Cno having count(Sno)>=5 and Cno like '3%' ——分组查询与模糊查询 (师)select Cno,avg(Degree) from score where Cno like '3%' group by Cno having count(Sno)>=5 ——聚合函数 count 13、select Sno from Score where Degree between 70 and 90 14、select Sname,Cno,degree from student,score where student.Sno=score.Sno (师)select Sname,Cno,degree from score join student on score.sno=student.sno ——连接查询,join on 15、select Sno,Cname,degree from course,score where course.cno=score.cno (师)select Sname,Cno,degree from score join course on score.cno=course.cno 16、select Sname,Cname,degree from student, course,score where student.Sno=score.Sno and course.cno=score.cno (师)select Sname,Cno,degree from score join student on score.sno=student.sno join course on score.cno=course.cno 17、select avg(degree) from score where sno in (select sno from student where class='95033') ——离散查询 18、select Sno,Cno,rank from score,grade where score.degree between low and upp 19、select * from score where cno='3-105' and degree>(select degree from score where sno='109'and cno='3-105')——第一种理解 select * from score where cno='3-105' and degree>(select max(degree) from score where sno='109')——理解二 20、select * from score b where degree <(select max(degree) from score a where a.cno=b.cno) select * from score where degree not in (select max(degree) from score group by cno having count(sno)>1) (师)select * from score where sno in (select sno from score group by sno having count(*)>1) and degree <(select max(degree) from score ) select * from score a where sno in (select sno from score group by sno having count(*)>1) and degree <(select max(degree) from score b where b.cno=a.cno ) 21、select * from score where cno='3-105' and degree>(select degree from score where sno='109'and cno='3-105') 22、select sno,sname,sbirthday from student where datediff(year,sbirthday,getdate())=(select datediff(year,sbirthday,getdate()) from student where sno='108') select * from student where year(sbirthdy)=(select year(sbirthday) from student where sno='108') 23、select cno,sno,degree from score where cno=(select cno from course ,teacher where course.tno=teacher.tno and teacher.tname='张旭') (师)select * from score where cno in(select cno from course where tno in(select tno from teacher where tname='张旭')) 24、select tname from teacher where tno in (select tno from course where cno in (select cno from score group by cno having count(*)>5)) 25、select * from student where class in('95033','95031')或者select * from student where class ='95033'or class='95031' 26、select distinct cno from score where degree>85 27、select cno,sno,degree from score where cno in (select cno from course ,teacher where course.tno=teacher.tno and teacher.depart='计算机系') (师)select * from score where cno in(select cno from course where tno in(select tno from teacher where depart='计算机系')) 28、select tname,prof from teacher where depart='计算机系' and prof not in (select prof from teacher where depart='电子工程系') union select tname,prof from teacher where depart='电子工程系' and prof not in (select prof from teacher where depart='计算机系') select tname,prof from teacher a where prof not in (select prof from teacher b where b.depart != a.depart) 29、select * from score where cno='3-105' and degree>any (select degree from score where cno='3-245')order by degree desc——any其中任何一个、all所有 30、select * from score where cno='3-105' and degree>(select max(degree) from score where cno='3-245') 31、select tname,tsex,tbirthday from teacher union select sname,ssex,sbirthday from student 32、select tname,tsex,tbirthday from teacher where tsex='女' union select sname,ssex,sbirthday from student where ssex='女' 33、select * from score a where degree<(select avg(degree)from score b where a.cno=b.cno) 34、select tname,depart from teacher a where exists(select * from course b where a.tno=b.tno); select tname,depart from teacher,course where Teacher.tno=Course.tno (师)select tname,depart from teacher where tno in( select tno from course where cno in( select distinct cno from score)) 35、select tname,depart from teacher a where not exists(select * from course b where a.tno=b.tno); (师)select tname,depart from teacher where tno not in( select tno from course where cno in( select distinct cno from score)) 36、select class from student where ssex='男'group by class having count(*)>=2; 37、 select * from student where sname not like'王%'; 38、select sname as 姓名,datediff(year,sbirthday,getdate()) as 年龄 from student select sname as 姓名,year(getdate())-year(sbirthday) as 年龄 from student 39、select sname,sbirthday as 最大 from student where sbirthday =(select min (sbirthday) from student) union select sname,sbirthday as 最小 from student where sbirthday =(select max(sbirthday) from student) (师)select min (sbirthday),max(sbirthday) from student 40、select class,sname,sbirthday from student order by class desc,sbirthday; 41、select x.tname,y.cname from teacher x,course y where x.tno=y.tno and x.tsex='男'; select tname,cname from teacher ,course where teacher.tno=course.tno and tsex='男' 42、select * from score where degree=(select max(degree)from score); (师)selsct top 1 * from score order by degree desc——只适用于有一个最高分 43、select sname from student where ssex=(select ssex from student where sname='李军'); 44、select sname from student where ssex=(select ssex from student where sname='李军') and class=(select class from student where sname='李军'); 45、select * from score where sno in(select sno from student where ssex='男') and cno=(select cno from course where cname='计算机导论');