摘要: 这是博问中的一个问题:http://q.cnblogs.com/q/39172/ 我的方案如下:function isOverlap(idOne,idTwo){ var objOne=$("#"+idOne), objTwo=$("#"+idTwo), offsetOne = objOne.offset(), offsetTwo = objTwo.offset(), topOne=offsetOne.top, topTwo=offsetTwo.top, leftOne=offsetOne.left,... 阅读全文
posted @ 2012-07-25 11:20 artwl 阅读(1294) 评论(0) 推荐(0) 编辑

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var ME = {
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