Reverse Vowels of a String Leetcode

Write a function that takes a string as input and reverse only the vowels of a string.

Example 1:
Given s = "hello", return "holle".

Example 2:
Given s = "leetcode", return "leotcede".

Note:
The vowels does not include the letter "y".

 

这道题一开始没想到stirng可以变成char的array，就做复杂了。。。边界的时候还需要挺注意的。

public class Solution {
    public String reverseVowels(String s) {
        if (s == null || s.length() == 0) {
            return s;
        }
        int left = 0, right = s.length() - 1;
        Set<Character> vowel = new HashSet<>(Arrays.asList(new Character[] {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}));
        StringBuilder newS = new StringBuilder();
        while (left < s.length()) {
            while (left < s.length() && !vowel.contains(s.charAt(left))) {
                newS.append(s.charAt(left));
                left++;
            }
            while (right >= 0 && !vowel.contains(s.charAt(right))) {
                right--;
            }
            if (right >= 0) {
                newS.append(s.charAt(right));
            }
            left++;
            right--;
        }
        return newS.toString();
    }
}

如果变成char array就很好做了

public class Solution {
    public String reverseVowels(String s) {
        if (s == null || s.length() == 0) {
            return s;
        }
        int left = 0, right = s.length() - 1;
        Set<Character> vowel = new HashSet<>(Arrays.asList(new Character[] {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}));
        char[] str = s.toCharArray();
        while (left < right) {
            while (left < right && !vowel.contains(str[left])) {
                left++;
            }
            while (left < right && !vowel.contains(str[right])) {
                right--;
            }
            char tmp = str[left];
            str[left] = str[right];
            str[right] = tmp;
            left++;
            right--;
        }
        return new String(str);
    }
}

需要注意的是char数组转成string有这两种方法：

new String(charArray);

String.valueOf(charArray);