JLOI2015 城池攻占

Description

 

Input

Output

 

Sample Input

5 5
50 20 10 10 30
1 1 2
2 0 5
2 0 -10
1 0 10
20 2
10 3
40 4
20 4
35 5

Sample Output

2
2
0
0
0
1
1
3
1
1
 

Data Constraint

 
 
 
 首先一条链的数据我们可以用堆自下而上维护还活首的骑士,判断攻击力最小的能否攻破,能则给堆打整体标记
由链推广到树,我们把堆变成可并堆即可
 
#include<cstdio>
#include<cstdlib>
#include<algorithm>
#include<cmath>
#include<cstring>
#include<vector>
using namespace std;
typedef long long ll;

vector<int> v[300011];
struct node{
    node *ls;
    node *rs;
    ll val,mul,add;
    int dist,peo;
    node(){
        ls=rs=NULL;
        mul=1;add=0;
        val=0;dist=0;
        peo=0;
    }
};

node *root[300011];
int que[300011],g[300011],next[300011],y[300011],f[300011],a[300011];
ll vs[300011],h[300011],atk[300011];
int st[300011],dep[300011],ciy[300011],scr[300011];
int n,m,tt,i;

void star(int i,int j)
{
    tt++;
    next[tt]=g[i];
    g[i]=tt;
    y[tt]=j;
}

void bfs()
{
    int l,r,x,j,k;
    l=r=1;
    que[l]=1;
    dep[1]=1;
    while(l<=r){
        x=que[l];
        j=g[x];
        while(j!=0){
            k=y[j];
            r++;
            que[r]=k;
            dep[k]=dep[x]+1;
            j=next[j];
        }
        l++;
    }
}

void change(node *&a,ll x,ll z)
{
    if(z!=1){
        a->val*=z;
        a->add*=z;
        a->mul*=z;
    }
    if(x){
        a->val+=x;
        a->add+=x;
    }
}

void down(node *a)
{
    if(a->mul!=1||a->add!=0){
        if(a->ls!=NULL)change(a->ls,a->add,a->mul);
        if(a->rs!=NULL)change(a->rs,a->add,a->mul);
        a->mul=1;
        a->add=0;
    }
}

node *Merge(node *a,node *b)
{
    if(a==NULL)return b;
    if(b==NULL)return a;
    if(a->val>b->val)swap(a,b);
    down(a);
    a->rs=Merge(a->rs,b);
    if(a->ls==NULL||a->ls->dist<a->rs->dist)swap(a->ls,a->rs);
    if(a->rs==NULL)a->dist=0;
    else a->dist=a->rs->dist+1;
    return a;
}

void Add(int x)
{
    node *ts;
    int i;
    for(i=0;i<v[x].size();i++){
        ts=new node();
        ts->val=atk[v[x][i]];
        ts->peo=v[x][i];
        root[x]=Merge(root[x],ts);
    }
}

void work()
{
    int i,x,po,j;
    for(i=n;i>=1;i--){
        x=que[i];
        Add(x);
        for(j=g[x];j;j=next[j])root[x]=Merge(root[x],root[y[j]]);
        while(root[x]!=NULL){
            if(root[x]->val<h[x]){
                scr[x]++;
                po=root[x]->peo;
                ciy[po]=dep[st[po]]-dep[x];
                down(root[x]);
                root[x]=Merge(root[x]->ls,root[x]->rs);
            }
            else break;
        }
        if(root[x]!=NULL){
            if(a[x]==0)change(root[x],vs[x],1);
            else change(root[x],0,vs[x]);
        }
    }
    while(root[1]!=NULL){
        po=root[1]->peo;
        ciy[po]=dep[st[po]];
        root[1]=Merge(root[1]->ls,root[1]->rs);
    }
    for(i=1;i<=n;i++)printf("%d\n",scr[i]);
    for(i=1;i<=m;i++)printf("%d\n",ciy[i]);
}

int main()
{
    scanf("%d%d",&n,&m);
    for(i=1;i<=n;i++)scanf("%lld",&h[i]);
    for(i=2;i<=n;i++){
        scanf("%d%d%lld",&f[i],&a[i],&vs[i]);
        star(f[i],i);
    }
    for(i=1;i<=m;i++){
        scanf("%lld%d",&atk[i],&st[i]);
        v[st[i]].push_back(i);
    }
    bfs();
    work();
}

 

posted on 2015-05-08 11:34  razorjxt  阅读(172)  评论(0编辑  收藏  举报