242 Valid Anagram
Given two strings s and t, write a function to determine if t is an anagram of s. For example, s = "anagram", t = "nagaram", return true. s = "rat", t = "car", return false. Note: You may assume the string contains only lowercase alphabets. Follow up: What if the inputs contain unicode characters? How would you adapt your solution to such case?
数组;--键值对
public class Solution { public boolean isAnagram(String s, String t) { int[] alphabet = new int[26]; for (int i = 0; i < s.length(); i++) alphabet[s.charAt(i) - 'a']++; for (int i = 0; i < t.length(); i++) alphabet[t.charAt(i) - 'a']--; for (int i : alphabet) if (i != 0) return false; return true; } }
follow up:
public boolean isAnagram(String s, String t) { if (s.length() != t.length()) { return false; } HashMap<Character, Integer> map = new HashMap<>(); for (int i = 0; i < s.length(); i++) { map.put(s.charAt(i), map.getOrDefault(s.charAt(i), 0) + 1); map.put(t.charAt(i), map.getOrDefault(t.charAt(i), 0) - 1); } for (Character c : map.keySet()) { if (map.get(c) != 0) { return false; } } return true; }