06 2012 档案
摘要：class A{public: A& operator += (const A&) {return *this;}; A& operator = (const A&) {return *this;};};class B:public A{public: B(){}; virtual ~B(){};};int main(){ A a; B b; b +=a; b = a; //invalid return 0;} 为什么 b += a;可以编译通过，但是b = a不行呢 ??因为operator =很特殊，即使你没有写，compiler也要生产一个，所以已经有一个
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摘要：#include <complex>#include <iostream>using namespace std;int main(void ){ complex< int> z(20, 200); cout << abs< int>(z) << endl; return 0;}According to the C++ ISO spec, §26.2/2:The effect of instantiating the templatecomplexfor any type other thanfloat,doub
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